**Answer:**

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

**Step-by-step explanation:**

**Given: **uniform distribution with min and max values of 18 and 33 respectively.

**To find :** probability density for upper cumulative frequency i.e 25.8 at least means x25.8 upto 33 cm i.e the maximum limit of function.

**Solution:**

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em><em> </em>

=1/(33-18)=1/15=0.0667.

this is probability density function.

**here the x=25.8 , a=18 and b=33 **

for** lower cumulative **frequency it defines as ;

**P(x,a,b)**= =25.8-18/33-18=**0.52**

for **upper cumulative** frequency it defines as ;

**Q(x,a,b)**=b-x/b-a=33-25.8/33-18=**0.48**

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i**.e. Q(x,a,b)=0.48**

The probability that randomly selected road will be at least 25.8 cm long will be 48%.