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2 years ago

Can someone explain how to get the right answers thx

Mathematics

1 answer:

Free_Kalibri [48]2 years ago

4 0

Idk exactly what those angles are called. I think supplementary interior. Which means they add up to 180°
So, (4x-2)+(6x-8)=180
Simplify. 10x-10=180
Now we need to get x by itself so add 10 to both sides to get 10x=190
Then divide by 10 to get x by itself x=190/10
So x=19

Hope this helped!!!

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The length of Rectangle A is 20 inches and the width is 4 inches. The length of Rectangle B is

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8 inches

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3 years ago

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If I plan to run 400 yards and I have completed 80%, how many yards do I have left?

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You have 80 yards left to run.

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7 0

3 years ago

Please show work and thank youuu

Assoli18 [71]

Answer: $6\sqrt{3}$

======================================================

Explanation:

Method 1

We can use the pythagorean theorem to find x.

$a^2+b^2 = c^2\\\\6^2+x^2 = 12^2\\\\36+x^2 = 144\\\\x^2 = 144-36\\\\x^2 = 108\\\\x = \sqrt{108}\\\\x = \sqrt{36*3}\\\\x = \sqrt{36}*\sqrt{3}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 2

Use the sine ratio to find x. You'll need a reference sheet or the unit circle, or simply memorize that sin(60) = sqrt(3)/2

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(60^{\circ}) = \frac{x}{12}\\\\\frac{\sqrt{3}}{2} = \frac{x}{12}\\\\x = 12*\frac{\sqrt{3}}{2}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 3

Similar to the previous method, but we'll use tangent this time.

Use a reference sheet, unit circle, or memorize that tan(60) = sqrt(3)

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{x}{6}\\\\\sqrt{3} = \frac{x}{6}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 4

This is a 30-60-90 triangle. In other words, the angles are 30 degrees, 60 degrees, and 90 degrees.

Because of this special type of triangle, we know that the long leg is exactly sqrt(3) times that of the short leg.

$\text{long leg} = (\text{short leg})*\sqrt{3}\\\\x = 6\sqrt{3}\\\\$

The short leg is always opposite the smallest angle (30 degrees).

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1 year ago