Answer:
D. If all of the offspring are short-tailed, the unknown individual is the homozygous dominant genotype.
Explanation:
The short tail phenotype is completely dominant over the long tail phenotype. When a short tailed salamander with unknown genotype is crossed with a homozygous recessive long tailed salamander, the cross is called testcross. Lets assume that the allele "S" gives "short tail" phenotype while the allele "s" gives "long tail" phenotype.
If the "short tailed salamander" with unknown genotype is homozygous dominant (SS), the process of the testcross will express only dominant trait (cross 1). On the other hand, if the "short tailed salamander" with unknown genotype is heterozygous dominant (Ss), segregation of alleles during gamete formation would form two types of gametes (cross 2). The 50% progeny would express the "long tail" phenotype while rest 50% will express the "short tail" phenotype.
mantle
Explanation:
yea I'm pretty sure that's it
Answer: The effects of which are devastating to human life, flora and fauna, which depend on these resources for their survival. Contamination of water causes disruptions of food chains and destruction of ecosystems. A deadly by-product of this water pollution is the spread of water-borne diseases such as cholera, typhoid etc.
Explanation:
Answer:
Not that often
Explanation:
Exponential growth can only occur if there are unlimited resources, no competition or no predators.
Answer:
1/2
Explanation:
The allele for the red-green color blindness is X-linked recessive. The father of the woman was colorblind (X^cY) which means that the woman is a carrier for the allele and has genotype (X^cX). The genotype of the colorblind male would be X^cY. A cross between a carrier woman and a color-blind man would produce progeny in following ratio= 1/2 colorblind daughter: 1/2 normal daughter: 1/2 colorblind son: 1/2 normal son.
Therefore, there is a 50% probability that their first son is colorblind.
