Inside a personal computer, 5 memory chips fit inside a 1-inch section. How much space do 3 memory chips take up?

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

Which of the following is equivalent to 60 Superscript one-half?

vitfil [10]

Answer:c

Step-by-step explanation:

The Answer is C.

4 0

4 years ago

Se dispone de 800 000 para invertir. Una cuenta paga el 18% de interés anual, y otra paga el 21%. ¿Cuánto debe invertirse en cad

Genrish500 [490]

Se debe depositar $ 600 000 en la cuenta con 18 % de interés anual y $ 200 000 en la cuenta con 21 % de interés anual para recibir $ 150 000 en intereses.

<h3>¿Cuánto se debe invertir en cada cuenta para alcanzar las ganancias deseadas en un período dado?</h3>

En este problema tenemos un depósito repartido en dos cuentas, que adquiere ganancias de manera continua en el tiempo. En consecuencia, tenemos por interés compuesto la siguiente ecuación a resolver:

x · (18/100) + (800 000 - x) · (21/100) = 150 000

168 000 - (3/100) · x = 150 000

(3/100) · x = 18 000

x = 600 000

Se debe depositar $ 600 000 en la cuenta con 18 % de interés anual y $ 200 000 en la cuenta con 21 % de interés anual para recibir $ 150 000 en intereses.

Para aprender más sobre el interés compuesto: brainly.com/question/23137156

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4 0

2 years ago

From time to time police set up roadblocks to check cars to see if the safety inspection is up to date. At one such roadblock th

77julia77 [94]

Answer: Police can be 95% confident that true population proportion lies in (2%, 5%).

Step-by-step explanation:

Interpretation of confidence interval of population proportion : A person can be 95% confident that true population proportion lies in it.

Given : From time to time police set up roadblocks to check cars to see if the safety inspection is up to date. At one such roadblock they issued tickets for expired inspection stickers to 22 of 628 cars they stopped.

95% confidence interval for the true proportion of all drivers with expired inspections = (2%, 5%).

Interpretation : Police can be 95% confident that true population proportion lies in (2%, 5%).

7 0

3 years ago

The county animal park is shaped like a triangle. Two perpendicular sides of the park measure 2.3 miles and 3.4 miles.

denis-greek [22]

A. 3.91 m²
area of a triangle is (base x height)/2
b=3.4
h=2.3
(2.3)(3.4)=7.82
7.82/2=3.91
**the height of this triangle would be one of the sides because it is a right triangle (sides meet and form perpendicular lines, or a 90° angle)

7 0

3 years ago