A pond is freshly stocked with 6 brown trout and 18 lake trout. The first fisherman in the area catches and releases a trout. He
2 answers:
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The content of care package would be a board game and several snack packs.
Given is the weight of board game = 4 pounds.
The weight of one snack pack =
The total weight would be less than 25 pounds.
Solving for part A :
Let 'x' represents the number of snack packs.
So the weight of all snack packs would be 0.5x pounds.
Now weight of care pack = weight of board game + weight of all snack packs.
weight of care pack = 4 + 0.5x
But total weight must be less than 25 pounds.
So the inequality would be: 4 + 0.5x < 25
Solving for part B :
Solving the inequality 4 + 0.5x < 25
⇒ 4 + 0.5x - 4 < 25 - 4
⇒ 0.5x < 21
⇒ x < 42
Solving for part C :
Since x < 42 and x is an integer number, so x = 41.
She can include maximum of 41 snack packs in the care package.
Answer:
49 ft
Step-by-step explanation:
h(t) = 56t - 16t²
This is the equation of a parabola.
We must solve the equation to find the time (t) when the ball reaches its maximum height (h).
The coefficient of t² is negative, so the parabola opens downward, and the vertex is a maximum.
One way to solve this problem is to convert the equation to the vertex form.
We do that by completing the square.
Calculation:
h = -16t² + 56t
Divide both sides by -16 to make the coefficient of t² equal to 1.
(-1/16)h = t² - ⁷/₂t
Square half the coefficient of t
(-7/4)² = 49/16
Add and subtract it on the right-hand side
(-1/16)h = t² - ⁷/₂t + 49/16 - 49/16
Write the first three terms as the square of a binomial
(-1/16)h = (t - ⁷/₄)² - 49/16
Multiply both sides by -16
h = -16(t - ⁷/₄)² + 49
You have converted your equation to the vertex form of a parabola:
y = a(t - h)² + k = 0,
where (h, k) is the vertex.
h = ⁷/₄ and k = 49, so the vertex is at (⁷/₄, 49).
The time to reach maximum height is ⁷/₄ s = 1.75 s.
The graph below shows that the ball reaches a maximum height of 49 ft after 1.75 s.
