Answer:
value of x = 5.8 mm
Step-by-step explanation:
We have given,
Two right triangles EDH and EDG.
In right triangle EDH, EH = 56mm , DH = 35 mm
Using Pythagoras theorem we can find ED.
i.e EH² = ED²+DH²
56²=ED²+35²
ED²=56²-35²
ED = √(56²-35²) = 7√39 = 43.71 mm
Now, Consider right triangle EDG
Here, EG=44.8mm , GD = x+4 and ED = 7√39
Again using Pythagoras theorem,
EG² = ED² + DG²
44.8²= (7√39)²+ (x+4)²
(x+4)² = 44.8² - (7√39)²
x+4 = √(44.8² - (7√39)²)
x+4 = 9.8
or x = 9.8 - 4 = 5.8 mm
Hence we got the value of x = 5.8 mm
C. 4.45 cm. you take the circumference and divide it by pi to find the diameter
Answer:
75 points
Step-by-step explanation:
45÷60%×100%=75 points in total
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
<h3>
What is an electron?</h3>
- The electron is a subatomic particle with a negative one elementary charge electric charge.
- Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.
Electron in the hydrogen:
- Hydrogen has the simplest electron configuration to write because it just contains one electron.
- There is essentially only one electron surrounding the Hydrogen nucleus.
- Because hydrogen only has one electron, its configuration is 1s1.
- The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.
Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
Know more about electrons here:
brainly.com/question/860094
#SPJ4
The complete question is given below:
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:
A. at a0. the first Bohr radius
B. at slightly less than a0
C. at slightly more than a0
D. at 2 a0
E. at a0/2
Answer:
4 / 3
Step-by-step explanation:
cos θ = 3 / 5
cos 53 = 3 / 5
θ = 53
tan θ = sin θ / cos θ
sin 53 = 4 / 5
tan 53 = sin 53 / cos 53
= ( 4 / 5 ) / ( 3 / 5 )
= ( 4 / 5 ) x ( 5 / 3 )
= ( 4 x 5 ) / ( 5 x 3 )
tan 53 = 4 / 3
