First we write the mathematical model in a generic way:
"The stopping distance of an automobile is directly proportional to the square of its speed v"
d = kv ^ 2
Where,
k: proportionality constant.
We now look for the value of K:
d = kv ^ 2
90 = k ((70) * (5280/3600)) ^ 2
k = 90 / ((70) * (5280/3600)) ^ 2
k = 0.008538539 s ^ 2 / feet
The equation will then be:
d = (0.008538539) * v ^ 2
For v = 71 miles per hour we have:
d = (0.008538539) * ((71) * (5280/3600)) ^ 2
d = 92.6 feet
Answer:
a mathematical model that gives the stopping distance in terms of its speed v is:
d = (0.008538539) * v ^ 2
The stopping distance if the brakes are applied when the car is traveling at 71 miles per hour is:
d = 92.6 feet
Answer:
b
Step-by-step explanation:
I think
Answer:
I'm so sorry I can't help but you can try and use math-way to answer anyquestions regarding equations and such!
The distance travelled by an object is 50 m.
<h3>What is Distance?</h3>
The distance between two points is the length of the path connecting them.
Here, given equation of distance
S = 1/2 (u + v)t
Where s is the distance traveled by an object (in meters)
initial velocity u (in m/s)
final velocity v (in m/s).
t in seconds.
Now, given values are;
u = 8 m/s ; v = 12 m/s ; t = 5 sec.
S = 1/2 (8 + 12)5
S = 1/2 (20)5
S = 100/2
S = 50 m.
Thus, the distance travelled by an object is 50 m.
Learn more about Distance from:
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