All categories

3 years ago

Carrots and beets are roots. They are sweet due to sugar. How is this an adaptation for the plant's survival?

Chemistry

2 answers:

Maru [420]3 years ago

7 0

It helps with reproductive success.

irina1246 [14]3 years ago

7 0

A, it helps with reproductive success

You might be interested in

Why does common table salt (NaCl) have a high melting point?

schepotkina [342]

The correct answer is c

8 0

3 years ago

Nitrous oxide (n2o), or laughing gas, is commonly used as an anesthetic in dentistry and surgery. how many moles are present in

Gelneren [198K]

Answer is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.

V(N₂O) = 8.4 L.

V(N₂O) = n(N₂O) · Vm.

Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.

n(N₂O) = 8.4 L ÷ 22.4 L/mol.

n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>

5 0

3 years ago

A Jaguar runs 4209 meters at the of 1400 meters per minute

Scorpion4ik [409]

Could you please describe the question?

lmk once you are done!!

support me by marking as brainliest!!

4 0

3 years ago

How many mole of ZnCl2 will be produced from 55.0 g of Zn, assuming HCL is available in excess

Ilia_Sergeevich [38]

Answer:

0.84 mol

Explanation:

Given data:

Moles of ZnCl₂ produced = ?

Mass of Zn = 55.0 g

Solution:

Chemical equation:

2HCl + Zn → ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 55.0 g/ 65.38 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of Zn with ZnCl₂ from balance chemical equation.

Zn : ZnCl₂

1 : 1

0.84 : 0.84

So from 55 g of Zn 0.84 moles of zinc chloride will be produced.

8 0

3 years ago

Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40. 10 g. She knows that the molar mass of NH4NO3 is 80. 04

nexus9112 [7]

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

<h3>What are moles?</h3>

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

$\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}$

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

Learn more about moles here:

brainly.com/question/2396149

8 0

2 years ago