The empirical formula : MnO₂.
<h3>Further explanation</h3>
Given
632mg of manganese(Mn) = 0.632 g
368mg of oxygen(O) = 0.368 g
M Mn = 55
M O = 16
Required
The empirical formula
Solution
You didn't include the pictures, but the steps for finding the empirical formula are generally the same
- Find mol(mass : atomic mass)
Mn : 0.632 : 55 = 0.0115
O : 0.368 : 16 =0.023
- Divide by the smallest mol(Mn=0.0115)
Mn : O =

The empirical formula : MnO₂
Answer:
is there an option for silver? if so, silver is the answer.
Answer:
6.5 moles of Oxygen are required
Explanation:
Based on the reaction:
CH3OH + 1/2 O2 → CH2O + H2O
1 mole of methanol reacts with 1/2 moles O2 to produce 1 mole of formaldehyde and 1 mole of water.
Thus, to produe 13 moles of formaldehyde, CH2O, are needed:
13 moles CH2O * (1/2mol O2 / 1mol CH2O) =
<h3>6.5 moles of Oxygen are required</h3>
Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide
.
Explanation:
Number of moles is defined as the mass of substance divided by its molar mass.
The molar mass of
is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide
.