Answer:
pOH = 11.5
[H⁺] = 0.003 M
[OH⁻] = 3 × 10⁻¹² M
Explanation:
The computation is shown below:
Given that
pH = 2.5
Based on the above information
We know that
pH + pOH = 14 ⇒ pOH = 14 - pH
pOH = 14 - 2.5
pOH = 11.5
[H⁺] = 10^(-pH) = 10^(-2.5)
[H⁺] = 0.003 M
[OH⁻] = 10^(-pOH)
= 10^(-11.5)
= 3 × 10⁻¹² M
[OH⁻] = 3 × 10⁻¹² M
Hence, the above represents the answer
Q1)
we can use the ideal gas law equation to find the total pressure of the system ;
PV = nRT
where P - pressure
V - volume - 7 x 10⁻³ m³
n - number of moles
total number of moles - 0.477 + 0.265 + 0.115 = 0.857 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in K - 273 + 25 °C = 298 K
substituting the values in the equation
P x 7 x 10⁻³ m³ = 0.857 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 303.33 kPa
1 atm = 101.325 kPa
Therefore total pressure - 303.33 kPa / 101.325 kPa/atm = 2.99 atm
Q2)
partial pressure is the pressure exerted by the individual gases in the mixture.
partial pressure for each gas can be calculated by multiplying the total pressure by mole fraction of the individual gas.
total number of moles - 0.477 + 0.265 + 0.115 = 0.857 mol
mole fraction of He -

mole fraction of Ne -

mole fraction of Ar -

partial pressure - total pressure x mole fraction
partial pressure of He - 2.99 atm x 0.557 = 1.67 atm
partial pressure of Ne - 2.99 atm x 0.309 = 0.924 atm
partial pressure of Ar - 2.99 atm x 0.134 = 0.401 atm
Answer:
H⁺(aq) + OH⁻(aq) ⇒ H₂O(l)
Explanation:
Let's consider the molecular equation that occurs when aqueous solutions of hydrofluoric acid and potassium hydroxide are combined. This is a neutralization reaction.
HF(aq) + KOH(aq) ⇒ KF(aq) + H₂O(l)
The complete ionic equation includes all the ions and molecular species.
H⁺(aq) + F⁻(aq) + K⁺(aq) + OH⁻(aq) ⇒ K⁺(aq) + F⁻(aq) + H₂O(l)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
H⁺(aq) + OH⁻(aq) ⇒ H₂O(l)
The answer is A I believe, the subscript 2 indicates that there are two magnesium ions for each ion of chlorine. the chloride ion is twice the size of the magnesium ion. magnesium and chlorine form a double covalent bond. there are two chloride ions for each magnesium ion.