Answer:
3200 ft-lb
Step-by-step explanation:
To answer this question, we need to find the force applied by the rope on the bucket at time 
At 
After seconds, the weight of the bucket is 
Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.
If the upward direction is positive, the displacement after seconds is 
Since the well is 80 ft deep, the time to pull out the bucket is 
We are now ready to calculate the work done by the rope on the bucket.
Since the displacement and the force are in the same direction, we can write
Use and 
![=\left[63 t-0.2 t^{2}\right]_{0}^{36}](https://tex.z-dn.net/?f=%3D%5Cleft%5B63%20t-0.2%20t%5E%7B2%7D%5Cright%5D_%7B0%7D%5E%7B36%7D)
Answer:
128
Step-by-step explanation:
they are parralel
The answer to this question is true.
Answer:
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
m∠RPS=
------> external angle
so
m∠RPS=
we have
m∠RPS=
substitute the values
Solve for arc RS
Answer:
∠ H = ∠ J = ∠N = ∠ M
Step-by-step explanation:
Triangle MNP is similar to triangle HJK and both triangles are isosceles triangles.
If the angle P is greater than 90 degrees, then angles M and N are the equal angles of the isosceles triangle MNP.
Hence, angle M = angle N
Now, as Δ MNP and Δ HJK are similar so, ∠ M = ∠ H, ∠ N = ∠ J, and ∠ P = ∠K
Again ∠ H = ∠ J as Δ HJK is isosceles.
Therefore, ∠ H = ∠ J = ∠N = ∠ M (Answer)
