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3 years ago

Help with science for A P E X

Physics

1 answer:

eimsori [14]3 years ago

7 0

Answer:

inertia

Explanation:

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Which statement is true regarding the vectors shown.

kap26 [50]

Answer:

Y-> + F-> +G ->=E->

Explanation:

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2 years ago

Can I put an “I” for an argumentative essay?

masha68 [24]

Answer:

There is no place for first person in formal academic argumentative essay. However, you can use first person only if it has been asked to provide your personal opinion or reflection about the topic.

Explanation:

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3 years ago

A magnifier has a magnification of 8 x. How far from the lens should an object be placed so that it’s virtual image is at the ne

larisa86 [58]

The distance of the object from the lens is 3.12 cm.

<h3>What is magnification?</h3>

Magnification is the process of of enlarging an apparent size of an object.

<h3>Object distance</h3>

The object distance is calculated using the following lens formula;

$M = \frac{V}{U}$

where;

M is the magnification
V is the image distance
U is object distance

$- 8 = \frac{-25}{U} \\\\U = \frac{-25}{-8} \\\\U = 3.12 \ cm$

Thus, the distance of the object from the lens is 3.12 cm.

Learn more about object distance here: brainly.com/question/24894435

8 0

2 years ago

1.) A negative charge of -2.0x10-4 C and a positive charge of 8.0x10-4 C are

exis [7]

Answer:

The Force between the two charges is an attractive force of 16,000N

Explanation:

Expression for the electric force between the two charges is given by

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = - 2.0x10^-4C

q2 = + 8.0x10^-4C

r = 0.30 m

Substitute the given values in the above expression -

One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)

The attraction force is:

F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2

F= 16,000N

6 0

2 years ago

If the total mechanical energy of the block spring system is 512 J, what is the amplitude for this oscillation?

jekas [21]

Answer:

A = 2.26 m

Explanation:

Given that,

The total mechanical energy of the block spring system is 512 J

Let the spring constant, k = 200 N/m

We need to find the amplitude for this oscillation. The mechanical energy of the spring mass system is given by :

$E=\dfrac{1}{2}kA^2$

k is spring constant

$A=\sqrt{\dfrac{2E}{k}} \\\\A=\sqrt{\dfrac{2\times 512}{200}} \\A=2.26\ m$

So, the amplitude of the oscillation is 2.26 m

4 0

2 years ago