200N
Explanation:
600N-400N = 200N
Answer:
minimum stopping distance will be d = 75 m
Explanation:
Maximum force exerted by the bracket is given as
F = 9000 N
now we know that mass of the object is
m = 6000 kg
so the maximum acceleration that truck can have is given as



now for finding minimum stopping distance of the truck



That is the answer to your problem
25 km/hr I hope this helps;)