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gogolik [260]
4 years ago
14

In a ballistics test, a 28-g bullet pierces a sand bag that is 30cm thick. If the initial bullet velocity was 55 m/s and it emer

ged from the sandbag moving at 18m/s, what was the magnitude of the friction force (assuming it to be constant and the only force present) that the bullet experienced while it traveled through the bag
Physics
1 answer:
slega [8]4 years ago
6 0

Answer:

Explanation:

Given that,

The mass of the bullet is

M= 28g = 0.028kg.

Thickness oof sack bag

d = 30cm = 0.3m

Initial velocity of bullet Vi = 55m/s

Velocity at which the bullet emerges the sack bag is Vf = 18m/s

We want to calculate the frictional force present in the sack bag.

Using conservation of energy.

Work done by friction in the sack is equal to change in kinetic energy.

Work done by friction is given as

Wf = Fr × d

The distance is the thickness of the bag

Wf = Fr × 0.3

Wf = 0.3 • Fr

Change in kinetic energy is calculated by

∆K.E = ½mVf² — ½ mVi²

∆K.E = ½m(Vf² — Vi²)

∆K.E = ½ × 0.028 ( 18²-55²)

∆K.E = 0.014 × -2701

∆K.E = -37.814 J

Since

Work done by friction = ∆K.E

0.3 Fr = -37.814

Fr = -37.814/0.3

Fr = -126.05 N

The, negative sign show that frictional force is opposing the motion.

Fr = 126.05 N

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Answer:

value of fs,max under the circumstances is

f = 42.56 N

Explanation:

The formula is µ = f / N, where µ is the coefficient of friction, f is the amount of force that resists motion, and N is the normal force. Normal force is the force at which one surface is being pushed into another.

So f = µN

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5 0
3 years ago
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A circuit is supplied with a constant voltage. As the resistance of the circuit decreases, the power given to the circuit
Yakvenalex [24]

Here, we are required to determine the reaction of the power given to a circuit supplied with a constant voltage as the distance of the circuit decreases.

  • In a circuit supposed with a <em>constant voltage</em>, as the resistance of the circuit decreases, the power given to the circuit Increases as evident in the formular: P = V²/R

The power given to a circuit is given by the formula;

Power, P = V × I

where, V = voltage supplied

and I = Current through the circuit.

However, from Ohm's law;

V = I × R

In essence, I = V/R

By substituting, I = V/R into the equation P = V × I

Therefore, we have;

P = V²/R.

Ultimately, if the circuit is supplied with a constant voltage, As the resistance of the circuit decreases, the power given to the circuit Increases.

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3 years ago
Explain what physicists mean when they say that the de Broglie wavelength relates to the probability distribution wave function.
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Answer:

Because it unites particle and wave nature.

Explanation:

De Broglie wavelength can be defined as the,

\lambda =\frac{h}{mv}

Here, h is planks constant, m is the mass of electron, v is the velocity of electron.

Since the de Broglie wavelength can behave like the photon wavelength with respect to the  momentum

It unites particles and waves nature ,so De Broglie wavelengths is probability waves associated with the wave function according to physicists.

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A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10 m/s. The instan
gizmo_the_mogwai [7]

Answer:

The velocity just before hitting the ground is v_f = 30 m/s

Explanation:

From the question we are told that

    The initial speed is  u = 10 m/s

    The final speed is  v = 30 \ m/s

From the equations of motion we have that

      v^2 =u^2 + 2as

Where s is the distance travelled which is the height of the cliff

  So making it the subject of the the formula  we have that

        s = \frac{v^2 - u^2 }{2a}

Where a is the acceleration due to gravity with a value  a = 9.8m/s^2

       So

                  s = \frac{30^2 - 10^2 }{2 * 9.8 }

                  s = 40.8 \ m

Now we are told that was through horizontally with a speed of

      v_x =10 m/s

Which implies that this would be its velocity horizontally through out the motion

    Now it final  velocity vertically can be mathematically evaluated as

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Substituting values

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The resultant final velocity is mathematically evaluated as

       v_f = \sqrt{v_x^2 + v_y^2}

Substituting values

       v_f = \sqrt{10^2 + 28.3^2}

       v_f = 30 m/s

   

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