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andreyandreev [35.5K]
2 years ago
15

What is the magnitude of a vector if the x component is -12 m and the y component is 21m?

Physics
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

22.02

Explanation:

(-21)²+(12)²=r²

r=√585

r=22.02

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2 years ago
If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?
Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

y=y_{o}+V_{oy}t-\frac{g}{2}t^{2} (1)

Where:

y=0 is the final height of the ball

y_{o}=h is the initial height of the ball

V_{oy}=V_{o}sin(0\°)=0 is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

t=0.5 s is the time at which the ball lands

g=9.8 m/s^{2} is the acceleration due gravity

So, with these conditions the equation is rewritten as:

h=\frac{g}{2}t^{2} (2)

h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2} (3)

Finally:

h=1.22 m

4 0
3 years ago
M=20kg F=10N d=25m<br>Work done=?​
fomenos

w=f×d

w=10N×25m

w=250Nm

5 0
2 years ago
What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, start
Llana [10]

Answer:

v_f=41.65\frac{m}{s}

Explanation:

The final velocity is given by the following kinematic equation:

v_f=v_0+at

Here, v_0 is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

7.5min*\frac{60s}{1min}=450s

Now, we calculate the final velocity:

v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}

4 0
3 years ago
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irakobra [83]

Answer:

an apple because its gaining speed as it falls

Explanation:

5 0
3 years ago
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