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andreyandreev [35.5K]
2 years ago
15

What is the magnitude of a vector if the x component is -12 m and the y component is 21m?

Physics
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

22.02

Explanation:

(-21)²+(12)²=r²

r=√585

r=22.02

You might be interested in
5 points
Drupady [299]

Answer:

distance is not a vector. it is scalar

5 0
3 years ago
An electron moving with a velocity = 5.0 × 10 7 m/s enters a region of space where perpendicular electric and a magnetic fields
inna [77]

Answer:

The magnetic field is 2 \times 10^{-4} T

Explanation:

Given:

Velocity of electron v = 5 \times 10^{7} \frac{m}{s}

Electric field E = 10^{4} \frac{V}{m}

The force on electron in magnetic field is given by,

 F = qvB \sin \theta                      ......(1)

The force on electron in electric field is given by,

 F = qE                               ......(2)

Compare both equation,

   qE = qvB \sin \theta

Here \sin \theta = 1

  E = vB

  B= \frac{E}{v}

  B = \frac{10^{4} }{5 \times 10^{7} }

  B = 2 \times 10^{-4} T

Therefore, the magnetic field is 2 \times 10^{-4} T

5 0
3 years ago
What is the momentum of a 2000 kg mass moving at 3 meters per second
podryga [215]

Answer:

<h2>6000 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 3

We have the final answer as

<h3>6000 kg.m/s</h3>

Hope this helps you

3 0
3 years ago
A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 10.0 m/s2. A 20 kg ma
DIA [1.3K]

Answer

given,

mass = 100 kg

acceleration = 10 m/s²

A mass 20 kg slides over 100 kg block

acceleration = 3 m/s²

horizontal friction exerted by the 100 kg block on 20 kg

using newton's second law

F - f = 0

F = f

f = ma

f = 20 × 3

f = 60 N

now net force acting on the 100 kg block

F_net = m a

F_net = 100 x 10

F_net = 1000 N

after 20 kg block falls the acceleration of the bock

F = 1000 +60

F = 1060 N

acceleartion on the block

a = \dfrac{F}{m}

a = \dfrac{1060}{100}

a = 10.60 m/s²

3 0
3 years ago
A 300-kg bear grasping a vertical tree slides down at constant velocity. the friction force between the tree and the bear is:___
Nady [450]

3000 N of friction exists between the bear and the tree.

The bear goes down at a constant speed, thus there is no acceleration. The forces add up to zero. As a result, upward friction and downward weight result in zero  

i.e.,

F-mg=0

F = mg

F = (300 kg)/10 m/s^{2} (gravitational acceleration)

3000 N frictional force equals F.

How does friction force work?

  • Friction is the force that prevents two solid objects from rolling or sliding over one another. Even though frictional forces, such as the traction required to walk without slipping, may be advantageous, they can also be a significant hindrance to motion.

Between solid surfaces, there are three basic types of friction:

  • Rolling
  • Sliding.
  • Static.                                                                                                                   They are graded from strongest to weakest. Fluid friction happens when liquids or gasses are mixed together.

To learn more about Friction force, visit:

brainly.com/question/13707283

#SPJ4

3 0
1 year ago
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