What is the value of this expression when x = -6 and ? 4(x2 + 3) − 2y

Hi guys i cant get this question can yous please help me its due in two days

Natasha2012 [34]

Answer:

(2400+420).

Step-by-step explanation:

We can break this into the same pattern as the other numbers, giving us:

(60×40)+(60×7)

When we multiply these we get:

(2400+420).

7 0

4 years ago

In how many ways can you select a president and then a Vice President from a group of 5 students.

jeyben [28]

21 different ways............

3 0

3 years ago

Help please :) I would appreciate it if you also provided a explanation it's okay if there is none :))

Oksi-84 [34.3K]

Answer:

7x^2 + 7

Step-by-step explanation:

So you collect the "like-terms". 3x^2 is not the same as 7, however, 4x^2 has the same term as 3x^2, so you add those together and then join the 7 in the expression.

Hope that explanation makes sense

8 0

3 years ago

Read 2 more answers

Question 6 of 10

siniylev [52]

Answer:

You need to get a tutor!!!!!

Step-by-step explanation:

√

7. [c

2 = a

2 + b

2 − 2ab cos C.] (5 marks)

2. x

−4/3 +

y

16 = 1. [Verify that the point is on the curve. Find slope

dy

dx = 12 (at that point)

and the tangent y + 8 = 12(x + 2). (5 marks)

Rearrange the equation to get it in intercept form, or solve y = 0 for x-intercept and x = 0

for y-intercept.] (5 marks)

3. One. [Show that g

0

(t) < 0 ∀t ∈ R, hence g is strictly decreasing. Show existence. Show

uniqueness.] (5 marks)

Comment: Graphical solution is also acceptable, but arguments must be rigorous.

4. 4π(9 − 2

√

6) or 16.4π or 51.54 cm3

. [V =

R 2π

0

R Rh

0

2

√

R2 − r

2 rdrdθ, R = 3, Rh =

√

3.

Sketch domain. (5 marks)

V = 4π

R Rh

0

√

R2 − r

2 rdr, substitute R2 − r

2 = t

2

. (5 marks)

Evaluate integral V = −4π

R

√

R2−R2

h

R t

2dt.] (5 marks)

5. (a) (2,1,8). [Consider p~ − q~ = ~s − ~r.] (5 marks)

(b) p

3/5. [cosQ =

QP~ ·QR~

kQP~ k kQR~ k

.] (5 marks)

(c) 9

5

(j + 2k). [Vector projection = (QP~ · QRˆ )QRˆ .] (5 marks)

(d) 6

√

6 square units. [Vector area = QP~ × QR~ .] (5 marks)

(e) 7x + 2y − z = 8.

[Take normal n in the direction of vector area and n · (x − q).] (5 marks)

Comment: Parametric equation q + α(p − q) + β(r − q) is also acceptable.

(f) 14, 4, 2 on yz, xz and xy planes. [Take components of vector area.] (5 marks)

6. 1.625%. [A = πab ⇒ dA

A = da

a + db

b

. (5 marks)

Put a = 10, b = 16 and da = db = 0.1.] (5 marks)

7. 9/2. [Sketch domain: region inside the ellipse x

2 + 4y

2 = 9 and above the x-axis. (5 marks)

By change of order, I =

R 3

−3

R 1

2

√

9−x2

0

ydydx

3 0

2 years ago

Find the critical value needed to construct a 95% CI of a population mean with an unknown standard deviation and a sample size o

kaheart [24]

Answer:

$t_{\alpha/2}=-2.02, t_{1-\alpha/2}=2.02$

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

In order to find the critical value we need to take in count that we are finding the critical value for the population mean and without the standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . We need to calculate the degrees of freedom are given by:

$df=n-1=39-1=38$

We can find the critical value using the following excel codes:

"=T.INV(0.025;38)" or "T.INV(1-0.025;38)"

And the critical values would be given by:

$t_{\alpha/2}=-2.02, t_{1-\alpha/2}=2.02$

7 0

3 years ago