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ser-zykov [4K]
3 years ago
13

Write the equation of the line that passes through the given points. Include your work in your final answer. Type your answer in

the box provided or use the upload option to submit your solution.
(2, 3) and (2, 5)
Mathematics
1 answer:
Harman [31]3 years ago
3 0
The equation you use for the slope of this kind of problem is (y2-y1)/(x2-x1). x1 is the first X coordinate, x2 is the second, y1 is the first y coordinate, y2 is the second.

(5-3)/(2-2)
2/0
This equation has an UNDEFINED SLOPE, as it is just a vertical line.
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A plane travels at a constant speed. It takes 6 hours to travel 3360 miles. A. What is the planes speed in miles per hour? B. At
NemiM [27]

Answer:

the plans can go 560 miles per hour and in 10 hours it can travel 5600 miles

Step-by-step explanation:

1st divide miles over hour so you have to do 3360/6 and the solution you get for that equation is how far the plane can go in miles per hour 2nd for the second question you have to multiply your unit rate by the 10 hours so since our unit rate was 560 miles per hour you would multiply 360 and 10.

4 0
3 years ago
Read 2 more answers
Show one way to count $82 to $512
mylen [45]
What do u mean like 82+82?
4 0
3 years ago
Read 2 more answers
11 PTS! 5 STARS! THANKS ON PROFILE AND QUESTION1 FIRST TO ANSWER ALL 5 GETS BRAINLIEST!
denis-greek [22]
1) Answer: 21
As y varies directly with x, this means that the ratio y/x is always a constant.
In other words, the equation can be written as y = kx, where k is a constant term.

Thus, -\frac{14}{4} = -\frac{y}{6}
y = 21

2) Answer: C
Exactly the same process as above.
Here's another method:
25 = k(140)
k = 25/140 = 5/28

Thus, when y = 36, 36 = kx
36 = 5/28(x)
36 * 28/5 = x; x = 201.6

3) 9 = k(12)
9/12 = k and k = 3/4

4) On the graph, it hits y = 1 at x = 4.
Thus, we can rewrite the equation as:
y = (1/4)x, where the constant term is 1/4

5) y = kx
The distance represents the x-ordinates, and the time represents the y-ordinates.

9.5/475 = 0.02
4 = 0.02(x), in hours.
x = 200 miles.
4 0
3 years ago
A circular swimming pool has diameter 60 feet and is centered in a fenced-in square region measuring 80 feet by 80 feet. a concr
borishaifa [10]
If I read the question correctly, the information about the 80x80 fencing and the grass region are all irrelevant information. 

In order to find the area of the side walk we are going to use the formula A=pi(r^2) where r = the radius. The diameter of the pool is 60 feet and the the sidewalk is 5 feet bigger all around meaning we had 5 feet to both sides of this 60 feet giving you an overall diameter of 70 feet (or 60 + 5*2). To find the radius take half of the diameter. 70/2 = 35. 

Now we plug in 35 to the equation. A = Pi(35^2) = 1225pi. Leave your answer like this as we are not finished and will need to round at the end for an accurate answer. This is NOT the end, that number is the area of the sidewalk AND the pool.

The sidewalk is not a full circle, just a border so we now have to find the area of the actual pool and subtract it from this 1225pi for the sidewalk's area. Same formula, Area = pi(r^2). The diameter of the pool is 60 meaning the radius is 30 (or 60/2). Plug into the equation, pi(30^2) = 900pi.

Now do 1225pi - 900pi to get 325pi. Break out your calculator and hit the approximation button. 325pi is approximately 1021.018 if rounded to 3 decimal places.

The area of the 5-foot wide sidewalk encircling the pool is approximately 1021.018 square feet. 


5 0
3 years ago
One analog clock loses 3 minutes every 2 hours and another analog clock gains 3 minutes every 4 hours. At noon, the owner sets t
Nadusha1986 [10]

Answer:

12 noon

Step-by-step explanation:

Clock 1 loses 3 minutes every 2 hours. Now, 2 hours = 120 minutes.

This means, it has speed of 120 - 3 = 117 minutes for every 2 hours.

Thus, in 1 hours, it's speed = 117/2 = 58.5 min/hr

Clock 2 gains 3 minutes every 4 hours

Which means in an hour, it gains ; 4/3 minutes

Thus, it's speed an hour is; 60 + 4/3 = 61.333 min/hr

Now, When he returns home in less than two weeks, the clocks show the same time.

let's say the number of hours he was away is x. For the 2 clocks to show the same time, it means they have to show it by 12 noon at another day since it was at noon that he set the correct times before leaving.

Thus, they will both be showing 12 noon.

6 0
3 years ago
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