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Shtirlitz [24]
4 years ago
15

According to the empirical rule, if the data form a "bell-shaped" normal distribution, ________ percent of the observations will

be contained within 2 standard deviations around the arithmetic mean.

Mathematics
1 answer:
jekas [21]4 years ago
5 0
According to empirical rule, the area under the normal distribution or "bell-shaped curve", when plotted as a function of the z-parameter can be defined in terms of percentages.
The z-parameter (or z-score) is defined as
z= \frac{x- \mu }{ \sigma }
where
x =  value of random variable,
μ = the mean,
σ = standard deviation,

The total area under the curve = 1.
The curve below shows that within 2 standard deviations from the mean, the total area under the curve is 95%  of the total area.



Answer: 95%

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Answer:

k=6

Step-by-step explanation:

42 ÷ 7 = 6

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Last spring 12 birds ate 8 cups of birdseed in one month. If I am expecting 18 birds this month, how
elena55 [62]

Simplified Ratio:  <u>3 : 2</u>

Birds / Cups

6 / 4

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18 / 12

You need 12 cups of birdseed if you're expecting 18 birds this month.

7 0
3 years ago
Simplify the expression 5^3 x 5^-5
kotykmax [81]

Answer:

\frac{1}{5^2} --- 1 over 5 squared

Step-by-step explanation:

When multiplying terms with a common base, you just add the exponents:

x^a\times x^b=x^{a+ b}

That's true even when you don't have any exponents.

5\times5=5^1\times5^1=5^{1+1}=5^2=25

\rightarrow5^3\times5^{-5}\\\rightarrow5^{3-5}\\\rightarrow5^{-2}

A negative exponent isn't fully simplified, so there's another rule to use:

x^{-y}=\frac{1}{x^y}

That is '1 over x to the y' if it's too small to read.

\rightarrow5^{-2}=\frac{1}{5^2}

4 0
2 years ago
Read 2 more answers
The values of 60, 62, and 84 were common to both samples. The three values are identified as outliers with respect to the age-gr
postnew [5]

Answer:

Only 60 is an identified outlier

Step-by-step explanation:

Given

<u>Age group: 40 to 50</u>

Min = 60           Q_1 = 70           Median= 73

Q_3 = 76              Max = 85

<u>Conditions for outlier</u>

Value > Q_3 + 1.5 * IQR

Value < Q_1 - 1.5 * IQR

<em>See attachment for complete question</em>

<u>Required</u>

Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years

First, calculate the IQR of group 40 to 50.

This is calculated as:

IQR = Q_3 - Q_1

Where:

Q_3 = 76 and Q_1 = 70

So:

IQR = 76 - 70

IQR = 6

<em>Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)</em>

<u></u>

<u>Testing 60</u>

<u>Condition 1</u>

Value > Q_3 + 1.5 * IQR

60 > 76 + 1.5 * 6

60 > 76 + 9

60 > 85 --- False

<u>Condition 2</u>

Value < Q_1 - 1.5 * IQR

60 < 70 - 1.5 * 6

60 < 70 - 9

60 < 61 --- True

<em>Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 62</u>

<u>Condition 1</u>

Value > Q_3 + 1.5 * IQR

62> 76 + 1.5 * 6

62 > 76 + 9

62 > 85 --- False

<u>Condition 2</u>

Value < Q_1 - 1.5 * IQR

62 < 70 - 1.5 * 6

62 < 70 - 9

62 < 61 --- False

<em>Because both conditions are false, then 62 is  not an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 84</u>

<u>Condition 1</u>

Value > Q_3 + 1.5 * IQR

84> 76 + 1.5 * 6

84 > 76 + 9

84 > 85 --- False

<u>Condition 2</u>

Value < Q_1 - 1.5 * IQR

84 < 70 - 1.5 * 6

84 < 70 - 9

84 < 61 --- False

<em>Because both conditions are false, then 84 is  not an outlier of group 40 - 50 years</em>

5 0
3 years ago
The base and height of a triangle is 36 and 12 respectively. It's area is ....... *
Leya [2.2K]

Answer:

the answer is of the question is 216

3 0
3 years ago
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