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1 year ago

_(_4×_3y-25) .we will

Mathematics

1 answer:

Wewaii [24]1 year ago

8 0

We have the following expression:

$-(-4x-3y-25)$

We must find an equivalent expression without parenthesis, for this, we can apply the product of signs and apply the law of signs

$4x+3y+25$

The answer, in conclusion, an equivalent expression is:

$-(-4x-3y-25)=4x+3y+25$

You might be interested in

How many math books and English books did Nicole purchase?

Ksju [112]

Create a system if equations to solve this.

First equation:
25m + 24e = 220

Second equation:
m + e = 9

Then you must solve the second equation for a variable.

Change m + e = 9 to e = 9 - m.

Then substitute (9 - m) for e in the first equation.

So 25m +24e = 220 becomes 25m + 24(9 - m) = 220.

Now you can solve the first equation because the only variable in it is m.

25m + 24(9 - m) = 220 (Original equation)
25m + 216 - 24m = 220 (Distribute)
m + 216 = 220 (Combine like terms)
m = 4 (Simplify)

Now plug in 4 for m in the second equation.

m + e = 9 (Original equation)
(4) + e = 9 (Substitute)
e = 5 (Simplify)

m represents Math Books and e represents English Books, so Nicole purchased 4 Math Books and 5 English Books.

6 0

3 years ago

Using the completing-the-square method, rewrite f(x) = x2 + 10x + 7 in vertex form

mr Goodwill [35]

Answer:

f(x) = (x - (-5))^2 + (-18)

Step-by-step explanation:

Given:

f(x) = x^2 + 10x + 7

Rewrite f(x) in vertex form

Solution:

f(x) = ax^2 + bx + c is a quadratic function.

The vertex form of f(x) is a(x - h)^2 + k, where (h, k) is the vertex.

=> f(x) = x^2 + 10x + 7

= x^2 + 10x + 25 - 18

= (x + 5)^ - 18

= (x - (-5))^2 + (-18)

=> f(x) can be rewritten in form of a(x - h)^2 + k, where (h, k) is the vertex, with a = 1, h = -5, k = -18

6 0

3 years ago

A cell phone company charges a flat fee of 20 dollars plus 3 cents a call. What is the total bill if there was a total of 200 ca

34kurt

Answer:

Total Bill = 4006 dollars

Step-by-step explanation:

A cell phone company charges a flat fee of 20 dollars plus 3 cents a call.

If there was a total of 200 calls for the month, the total charge by the cell phone company will be.

Let me convert all to cent first

100 cent = 1 dollar

20 dollar =20 *100

29 dollar = 2000 cent

Charge by the company for a call is 2003 cent

Let me put down the equation.

1 call = 2003 cent

200 calls =( 200 calls* 2003cent)/1 call

200 calls = 200 * 2003cent

200 calls = 400600 cent

Let's convert back to dollar

100 cent = 1 dollar

400600 cent = 400600/100

400600 cent = 4006 dollars

8 0

3 years ago

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$