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3 years ago

Q 2 Justify the following statements.

Chemistry

2 answers:

Karolina [17]3 years ago

7 0

I Think The answer is a I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you

snow_lady [41]3 years ago

4 0

Answer:

i am bor ed anyo ne wanna talk to me i am bo y

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How does a sample of hydrogen at 10 degrees Celsius compare to a sample of hydrogen at 350K?

Sophie [7]

Answer:

We can compare the both sample by taking into account the kinetic energy.

By increasing the temperature kinetic energy of gas molecules increased.

Explanation:

It is known that kinetic energy of molecules is increased by increasing the temperature.

We are given with two sample of hydrogen one is at 10°C and other is at 350 K.

Hydrogen sample at 10°C = 273.15 + 10 = 283.15 k

Thus one sample is at 283.15 K and other is at 350 K. So, the sample at higher temperature i.e 350 K will have more kinetic energy of molecules.

While the sample at 283.15 K will have less speed of molecule and kinetic energy.

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3 years ago

What will happen to the salt when mixed to liquid?

Pepsi [2]

Answer:

the salt dissolves in water because of covalent bonds.

Explanation:

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3 years ago

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Phenolphthalein meaning

Simora [160]

Answer:

Phenolphthalein is a chemical compound with the formula C20H14O4 and is often written as "HIn" or "phph" in shorthand notation. Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.

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3 years ago

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Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o

Gnom [1K]

Answer: The empirical formula for the given compound is $C_5H_7N$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

$C_xH_yN_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of $CO_2=21.363mg=21.363\times 10^3g=21363g$

Mass of $H_2O=6.125g=6.125\times 10^3g=6125g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, $\frac{12}{44}\times 21363=5826.27g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, $\frac{2}{18}\times 6125=680.55$ of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = $\frac{485.52}{97.73}=4.96\approx 5$

For Hydrogen = $\frac{680.55}{97.73}=6.96\approx 7$

For Nitrogen = $\frac{97.73}{97.73}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is $C_5H_7N_1=C_5H_7N$

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3 years ago

Which of the following is the correct equation for photosynthesis

Finger [1]

Answer:

6CO2 + 6H20 + ENERGY = C6H12O6 + 6O2

Explanation:

Carbon dioxide + water + energy from light produces glucose and oxygen

4 0

3 years ago