Answer:
Copper ions are reduced into copper atoms.
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Explanation:
During electrolysis, the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.
At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)
Thus the half equation is as follows:
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Answer:
Element Properties
atomic number 47
atomic weight 107.868
melting point 960.8 °C (1,861.4 °F)
boiling point 2,212 °C (4,014 °F)
specific gravity 10.5 (20 °C [68 °F])
oxidation states +1, +2, +3
electron configuration [Kr]4d105s1
hope that helps
D. 2
Explanation:
To be balanced, the hydrogen and chlorine atoms are both 2 and 2 in the products side. Hence, we must add a two to the HCl in order to have 2 hydrogens and 2 chlorines in the reactants.
Hope this helps, brainliest would be appreciated :)
The initial state of the compound Br2 is liquid. The final
state is then solid. We know for certain that the liquid state has higher energy
as compared to solid state. Due to this fact, Br2 must release energy to be in
solid form. Therefore, the change in enthalpy is:
ΔH = -7.4 kcal/nil
