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Lerok [7]
3 years ago
8

Rutherford used a gold foil experiment and discovered what part of an atom

Chemistry
1 answer:
slamgirl [31]3 years ago
7 0
Hihi!

During Rutherford's experiment<span> of shooting particles through a sheet of </span>gold foil <span>he had discovered that some were deflected! This had proved that an </span>atom<span> is actually a small dense nucleus surrounded by orbiting electrons!

I hope I helped!
-Loliarual</span>
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The pKa of the α‑carboxyl group of serine is 2.21 , and the pKa of its α‑amino group is 9.15 . Calculate the average net charge
sleet_krkn [62]

Answer:

Net charge in serine at pH equal to 8.30 is "0"

Explanation:

  • At pH > pK_{a}, carboxyl group exists as -CO_{2}^{-} (charged)
  • At pH < pK_{a}, carboxyl group exists as -COOH (neutral)
  • At pH > pK_{a}, amino group exists as -NH_{2} (neutral)
  • At pH < pK_{a}, amino group exists as -NH_{3}^{+} (charged)
  • So, at pH = 8.30, both carboxyl and amino group exists in charged state.
  • Net charge in serine at pH equal to 8.30 is "0".
  • Structure of serine at pH equal to 8.30 has been shown below.

8 0
3 years ago
Is the continental crust less dense or more dense ?
zheka24 [161]

Answer:

It is less dense. It is also less dense than the oceanic crust.

Hope this helps and if it did, please mark brainliest!

4 0
3 years ago
Read 2 more answers
5 points<br> What is the name of the atom pictured here? Use a periodic table if<br> needed. *
photoshop1234 [79]

Answer:

There is nothing attached to this question so I unfortunately cannot help you

Explanation:

3 0
3 years ago
If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat
In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

<em />

Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>
8 0
2 years ago
How does a tree get energy?
Snezhnost [94]
Your answer is B. It gets energy from the Sun.
Have a great day :)
6 0
2 years ago
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