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Lerok [7]
3 years ago
8

Rutherford used a gold foil experiment and discovered what part of an atom

Chemistry
1 answer:
slamgirl [31]3 years ago
7 0
Hihi!

During Rutherford's experiment<span> of shooting particles through a sheet of </span>gold foil <span>he had discovered that some were deflected! This had proved that an </span>atom<span> is actually a small dense nucleus surrounded by orbiting electrons!

I hope I helped!
-Loliarual</span>
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Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
viktelen [127]

Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

Mass of NH₃ = 100 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 100 / 17

Mole of NH₃ = 5.88 moles

Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e

Xmol of H₂ = (3 × 5.88)/2

Xmol of H₂ = 8.82 moles

Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:

Pressure (P) = 95 KPa

Temperature (T) = 15 °C = 15 + 273 = 288 K

Number of mole of H₂ (n) = 8.82 moles

Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

PV = nRT

95 × V = 8.82 × 8.314 × 288

95 × V = 21118.89024

Divide both side by 95

V = 21118.89024 / 95

V = 222.30 L

Thus the volume of Hydrogen needed for the reaction is 222.30 L

8 0
3 years ago
Free 100 for the boys​
Drupady [299]
Ok thanks wkwksnmenenenenenenwnwnnwnwnwnw
6 0
3 years ago
Read 2 more answers
Draw it draw lewis dot structures for each hypothetical molecule shown below, using the correct number of valence electrons for
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The first molecule is a sensible molecule having complete octet of each atom such as C, H and O whereas the second molecule having hydrogen present between the aldehyde and methyl group and thus showing hydrogen is making bond with aldehyde and methyl as well which is not possible because hydrogen only having one electron in its octet due to which it can only form a single bond by sharing its valence electron.

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3 years ago
How do the electrons in bonds (bonding domains) differ from lone pairs (non-bonding domains)?
max2010maxim [7]

The electrons in bonds (bonding domains) differ from lone pairs (non-bonding domains) is because the bonding domains are bonded to the central atom vs the lone pairs are just stuck on as extra electrons. The difference of bonding domains from non-bonding domains is that the bonding domains are bonded to the central atom and the non-bonding domains are just stuck on as extra electrons.

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Post laboratory reflections 1 write equation [2] in the net ionic form 2. describe what happens when strong acid acts on limesto
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It deteriorates. Definitely more than when you started.

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