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Lerok [7]
2 years ago
8

Rutherford used a gold foil experiment and discovered what part of an atom

Chemistry
1 answer:
slamgirl [31]2 years ago
7 0
Hihi!

During Rutherford's experiment<span> of shooting particles through a sheet of </span>gold foil <span>he had discovered that some were deflected! This had proved that an </span>atom<span> is actually a small dense nucleus surrounded by orbiting electrons!

I hope I helped!
-Loliarual</span>
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Answer:

Its main advantage is <em>they information fits on one line of text</em> <u>(thus works well when using the formula in paragraphs)</u>. Disadvantages are <em>they can be confusing for larger molecules</em>

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8 0
1 year ago
What are abiotic factor is the most important in the mono lake ecosystem?
Oxana [17]

Answer:

The salt water, bc the salt water substances little life forms in the  water so that there is not a lot of living form in the salt water

3 0
3 years ago
Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of
Arisa [49]

<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

<u>Explanation:</u>

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

\Delta x.\Delta p=\frac{h}{2\pi}

where,

\Delta x = uncertainty in position = d = 4.50\times 10^{-5}m

\Delta p = uncertainty in momentum  = m\Delta v

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h = Planck's constant = 6.627\times 10^{-34}kgm^2/s^2

Putting values in above equation, we get:

4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s

Hence, the uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

8 0
3 years ago
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kakasveta [241]
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4 0
3 years ago
Read 2 more answers
How many covalent bonds does and oxygen stone usually make in forming covalent compounds?
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Answer: Oxygen usually forms two covalent bonds or a covalent double bond.

Explanation:

A covalent bond is formed by the sharing of 2 electrons, 1 electron from each of the atoms sharing their electrons.

The number of bonds that each element can form depends on the number of valence (outermost) electrons it contains. Oxygen has 6 electrons in its valence shell and needs 2 more electrons thereby forming a double bond.

5 0
2 years ago
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