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Shalnov [3]
3 years ago
8

Write six and five hundredths in decimal form.

Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

5 hundredths: 0.05

6 hundredths: 0.06

Step-by-step explanation:

Reil [10]3 years ago
7 0
6.05 is six and five hundredths in decimal form.
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Answer:

The functions have the same y-intercept.

OPTION C is correct.

Step-by-step explanation:

<u>DEFINITIONS AND FORMULAS</u>

The equation of a linear graph is given to be:

y=mx+b

Where m is the slope of the graph and b is the y-intercept.

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p=-\frac{3}{2}r-5

Therefore, the y-intercept of the graph is given to be:

b=-5

<u>Function 2: Recall that the y-intercept of a graph is the y-value when x = 0.</u>

On checking the graph, we can see that when r = 0, p = -5.

Therefore, the y-intercept is:

b=-5

ANSWER

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OPTION C is correct.

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Answer:

\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

Step-by-step explanation:

So we want to find the derivative of the rational equation:

y=\frac{x^2-2x}{x^3+3}

First, recall the quotient rule:

(\frac{f}{g})'=\frac{f'g-fg'}{g^2}

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

f=x^2-2x\\f'=2x-2

g=x^3+3\\g=3x^2

So:

\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'

Use the above format:

\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

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