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Dmitry_Shevchenko [17]
2 years ago
15

I don’t understand what i can do

Mathematics
1 answer:
alexandr402 [8]2 years ago
4 0

Answer:

14.037

Step-by-step explanation:

3^{-3} +5+9\\

0.037+5+9

14.037

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The quotient of negative eight and the sum of a number and three
PolarNik [594]
For this case, the first thing we must do is define a variable.
 We have then:
 x: real number
 Now we write the expression:
 -8 / (x + 3)
 The number x can be all real different from minus three.
 Answer:
 
-8 / (x + 3)
 
With x different from -3.
6 0
3 years ago
Find derivative of the following problem ?
stepan [7]
Let u = x.lnx, , w= x and t = lnx;  w' =1 ;  t' = 1/x

f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)

let' find the  derivative u' of u
u = w.t
u'=  w't + t'w;  u' = lnx + x/x = lnx+1

u' = x+1 and f'(u) = ln(x+1).e^(xlnx)

finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x
4 0
3 years ago
Which of the following expressions is not equivalent to -5?
Elena L [17]

Answer:

-5/25

Step-by-step explanation:

25/(-5)=-5

-35/7=-5

-5/25=-1/5

35/(-7)=-5

hope I helped

5 0
2 years ago
Read 2 more answers
Please help I do not understand
STatiana [176]

Answer:

The coefficients are;

1,28,378 and 3,276

Step-by-step explanation:

For the binomial expansion, when we talk of the coefficients, we mean the whole numbers that stands before the alphabets

For example, the coefficient of x in 2x is 2

Back to the question;

(x + y)^28

= 28C0 x^28y^0 + 28C1 X^27y^1 + 28C2 x^26y^2 + 28C3 x^25y^3 + ..........

So the coefficients we are looking for are;

28C0 = 1

28C1 = 28

28C2 = 378

28C3 = 3,276

Kindly note that 28C0 is read as 28 combination zero and so on

3 0
2 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58 dash m​-by-5
svetoff [14.1K]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

5 0
3 years ago
Read 2 more answers
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