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sveta [45]
3 years ago
13

GIVING BRAINLIEST PLS HELP!!!

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

it's the first one

Explanation:

Have a great day hope it helps

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Could anyone help with this? :)
rjkz [21]
I think its d- theory
5 0
3 years ago
Can someone please answer this, ill give you brainliest and your earning 50 points.
Aleonysh [2.5K]

Answer:

Good morning! It's D. all of the above

Explanation:

Social backgrounds, culture, politics, education and economic reasoning might equally contribute to uncontrolled settlements. People live in disaster-prone areas partly for economic reasons. In the case of Semarang, where tidal flooding submerges houses, people stay due to economic factors.

Plus I took the test and got it right

_AnnieTheDreamGirl, 3/10/2022

6 0
2 years ago
Find f0, the magnitude of the upward force on the table due to the leg at (0, 0.
Katena32 [7]
Assuming that the table has 4 legs. the upward force is equal to the downwardd force. the downward force of the table is the weight of the table. so the upward force is also the weight of the table but in opposite direction, so the upward force in on one leg is 1/4 of the weight of the table
6 0
4 years ago
a roller coaster is traveling at 13m/s when it approaches a hill that is 400m long. heading down the hill, it accelerates 4.0m/s
Degger [83]
We will apply the equation:
2as = v² - u²
v = √(2as + u²)
v = √(2 x 4 x 400 + 13²)
v = 58 m/s

hope this helps
7 0
3 years ago
If you swim with the current in a river, your speed is increased by the speed of the water; if you swim against the current, you
Blababa [14]

Answer:

11.23%

Explanation:

Lets take

Speed of man in still water =u= 1.73 m/s

Speed of flow of water = v=0.52 m/s

When swims in downward direction then speed of man = u + v

When swims in upward direction then speed of man = u - v

Lets time taken by man when he swims in downward direction is t_1 and when he swims in downward direction is t_2

Lets distance is d and it will be remain constant in both the case

d=(u+v)t_1

d=(u-v)t_2

(1.73+0.52)t_1=(1.73-0.52)t_2

t_2=1.85t_1

Time taken in still water

2 d= t x 1.73

t=1.15 x d sec

t_1=0.44d\ sec

t_2=0.82d\ sec

total time in current = 0.82 +0.44 d=1.26 d sec

So the percentage time

percentage\ time =\dfrac{1.28-1.15}{1.15}

 Percentage time =11.32%

So it will take 11.32% more time as compare to still current.

5 0
3 years ago
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