C. Line crosses y-axis at 1. Line goes 1 unit down and 4 units across.
Apply the Law of Sines.
sin A sin B sin C
------- = -------- = --------
a b c
Inserting the given data,
sin 36 sin B sin C
--------- = -------- = --------
250 300 420
300 sin 36
Then 300 sin 36 = 250 sin B, and sin B = ---------------- = 0.705
250
Thus, arcsin B = 0.783 rad = 44.857 degrees, or about 45 degrees.
Taking B to be 45 degrees and the given angle 36 deg, then the 3rd angle must be 180 - (45+36) = 99 degrees (which is opposite the 420-ft side).
At this point we apply Heron's formula. You should look this up on the 'Net.
a + b + c 250 + 300 + 420
First, we calculate S = --------------- = ------------------------ = 970/2 = 485
2 2
and then calculate sqrt (S(S-A)(S-B)(S-C):
Area of triangle / lot is then:
A = sqrt(485(485-250)(485-300)(485-420))
= sqrt(485(235)(185)(65) )
= 37021 square feet
Answer:
The larger trampoline is larger in area by 75.36 feet²
Step-by-step explanation:
There are two trampolines here; the larger and the smaller one.
The trampoline's area can be found using the area of a circle which is πr² or πd²/4, where "r" and "d" represent radius and diameter respectively.
Here we will let D be <em>the diameter of the larger trampoline</em> and d should be taken as <em>the diameter of the smaller trampoline</em>.
So, the difference in area will be πD²/4 - πd²/4 = π/4 (D² - d²), where π is given as 3.14.
So, the area difference = 
× (14² - 10²) = × (196 - 100) = × (96) = 75.36 feet²
