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olga55 [171]
3 years ago
13

2. Light traveling in air (n1=1) hits a piece of glass at an angle of 45 degrees. If the glass has a refractive index of 1.5, wh

at angle should the light bend at?
Physics
1 answer:
irina [24]3 years ago
5 0

Answer:

28.1 degrees

Explanation:

Use formula: N_1Sin(Angle_1) = N_2Sin(Angle_2)

* use angles given

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Weight is mass x gravity, so you'd multiply the mass of the astronaut by the gravitational pull.

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4 years ago
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HELPPPPPPPPPPPPPPPPPPPPPPPPPP
aev [14]

Answer:

C

Explanation:

through the desk....here desk is the student's medium to hear the sound. its oblivious because when he lifts his head away from the desk he hears nothing else

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3 years ago
Assume that, when we walk, in addition to a fluctuating vertical force, we exert a periodic lateral force of amplitude 25 NN at
dexar [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  F = 25 \  N

   The frequency is   f = 1 \  Hz

   The mass of the bridge per unit length is  \mu  =  2000 \  kg /m

    The length of the central span is  d =  144 m

     The oscillation amplitude of the section  considered at the time considered is  A = 75 \ mm =  0.075 \  m

      The time taken for the undriven oscillation to decay to \frac{1}{e}  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            m =  \mu  *  d

=>        m =  2000 * 144

=>        m =  288000 \ kg

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 A(t) = A_o e^{-\frac{bt}{2m} }

Here b is the damping constant and the A_o is the amplitude of the section when it was undriven

So from the question  

               \frac{A_o}{e}  = A_o e^{-\frac{b6T}{2m} }

=>            \frac{1}{e}  =e^{-\frac{b6T}{2m} }

=>          e^{-1} =e^{-\frac{b6T}{2m} }

=>           -\frac{3T b}{m}  =  -1

=>         b  = \frac{m}{3T}

Generally the amplitude of the section considered is mathematically represented as

           A =  \frac{n * F }{ b *  2 \pi }

=>       A =  \frac{n * F }{ \frac{m}{3T}  *  2 \pi }

=>       n =  A  *  \frac{m}{3}  *  \frac{2\pi}{25}

=>       n = 0.075 *  \frac{288000}{3}  *  \frac{2* 3.142 }{25}

=>       n = 1810 \ people

3 0
3 years ago
If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 70 km/h . The c
olganol [36]

as it is given that curved marked the speed as v = 70 km/h

so we will first convert the speed into m/s

v = 70 km/h = 19.44 m/s

now we know that here friction force will provide centripetal force

F_c = F_f

As we know that centripetal force is given as

F_c = \frac{mv^2}{R}

\frac{mv^2}{R} = \mu_k mg

\frac{v^2}{R} = \mu_k g

v^2 = \mu_k R * g

19.44^2 = 0.5* R * 9.8

378 = 4.9 * R

R = 77.1 m

3 0
4 years ago
Read 2 more answers
I need HELP Please !!
aliya0001 [1]
You have to figure it out
5 0
3 years ago
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