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2 years ago

What does a animal and a plant cell have in common.

Physics

2 answers:

Allushta [10]2 years ago

8 0

Answer:

Structures that are common to plant and animal cells are the cell membrane, nucleus, mitochondria, and vacuoles. Structures that are specific to plants are the cell wall and chloroplasts.

Explanation:

if correct plzz brainliest :D

expeople1 [14]2 years ago

3 0

Answer:

Nucleus, cell membrane, cytoplasm and mitochondria

Explanation: They both have these 4 components, which is what they have in common.

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I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

3 0

3 years ago

Evaluate ( 64800 ms ) 2 to three significant figures and express the answer in Si units. Express your answer using three signifi

Sergeu [11.5K]

Answer:

42.0×10² second²

Explanation:

Here, time is given in milisecond

(64800 ms)²

= 4199040000 ms²

The SI unit is seconds

1 second = 1000 milisecond

$1\ milisecond=\frac{1}{1000}\ second$

$\\\Rightarrow 1\ milisecond^2=\left(\frac{1}{1000}\right)^2\ second^2$

$4199040000\ ms^2=4199040000\times \left(\frac{1}{1000}\right)^2\ second^2=4199.04\ second^2$

42.0×10² second²

6 0

3 years ago

An automobile moves on a level horizontal road in a circle of radius 30 m. The coefficient of

blondinia [14]

Answer:

v = 12.12 m/s

Explanation:

It is given that,

Radius of circle, r = 30 m

The coeﬃcient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

5 0

3 years ago

Which term is a scalar quantity?

balu736 [363]

Vector quantities have both magnitude and direction. Distance is a scalar quantity. It refers only to how far an object has traveled. For example, 4 feet is a distance; it gives no information about direction.

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3 years ago

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The wavelength of light is given by the velocity divided by the frequency. the velocity of blue light is 300,000,000 m/sec, and

s2008m [1.1K]

<span>Electromagnetic radiation are represented in waves. Each type of wave has a certain shape and length. The distance between two peaks in a wave is called the wavelength. It is indirectly related to the frequency which is the number of wave that pass per unit of time. Wavelength is equal to the speed of light divided by the frequency. We calculate as follows:

Wavelength = </span>300,000,000 m/sec / <span>650,000,000,000,000 per second
Wavelength = 4.62x10^-4 m</span>

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3 years ago

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