Answer:
Step-by-step explanation:
Neither.
It is a complex number. The - sign is the culprit. sqrt(-144) = i * sqrt(144) = 12 i
The "i" is an imaginary representation for the square root of -1. It is a definition for sqrt(-1). So a new category of number has been created. The ancients would have been profoundly surprised to learn that such a thing existed.
Step 
<u>Find the slope of the given line</u>
Let

slope mAB is equal to

Step 
<u>Find the slope of the line that is perpendicular to the given line</u>
Let
CD ------> the line that is perpendicular to the given line
we know that
If two lines are perpendicular, then the product of their slopes is equal to 
so

Step 
<u>Find the equation of the line with mCD and the point (3,0)</u>
we know that
the equation of the line in the form point-slope is equal to

Multiply by
both sides


therefore
the answer is
the equation of the line that is perpendicular to the given line is the equation 
Answer:
there are 3 1/6 pieces
Step-by-step explanation:
since 3 x 1/6=3/6.
another explanation:
(3/6)/(1/6)=(3/6) x (6/1) since you multiply by inverse when dividing fractions. Then, (3/6) x (6/1) = 18/6, which equals 3.
The height of the given trapezoid is 7.5 m.
Step-by-step explanation:
Step 1:
The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.
The trapezoid's area, 
Here
is the lower base length and
is the upper base length while h is the height.
Step 2:
In the given problem,
and
. Assume the height is h m.
The trapezoid's area 


So the height of the given trapezoid is 7.5 m.
I'd say that, if the angles S and U are equal, as the SV and UV segments move towards each other, they meet at vertex V, the angles they make, angle SVT and UVT, have to be equal, because the side TV is shared by both, and has the same direction.
now, side TV is on both triangles, and is shared by both, so is the same length, so TV on one triangle is equal to TV on the other
check the picture below
so, you have one Angle, another Angle, and then a Side
A A S