When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
Answer:
3.8
Step-by-step explanation:
We are going to plug in the values of the equation, so h(t)=-4.9^2+v0t+h0 will
now be h(t)=-4.9^2+0+70
Now we will find the a b and c of the equation, a=-4.9 b=0 c=70
Now we must find the discriminant of the equation, which the equation for that is D=b^2+(-4)(a)(c)
So D=1,372
Now we use the quadratic formula (see picture below for finished product)
Answer:
the answer is i think is 60.7