Given the Arithmetic sequence A1,A2,A3,A4 61, 74, 87, 100 What is the value of A15?

1 answer:

4 0

A15=243
74-61=13
87-61=13
So they're adding 13 every time.
A15 is 11 terms from A4 which is the last one you are given so 11*13=143
143+100=243

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3 years ago

(3j? - h) +3; use h=6, and j = 5

Drupady [299]

Answer:

Step-by-step explanation:

(3j-h)+3

Plug in numbers:

(3(5)-(6))+3

Solve:

(15-6)+3

9+3=12