<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
all of them except the last efg and bcd
1. 100000
2. 0.000000000001
3. 400
Find the median and mean of the data set below: 6 , 37 , 2 , 38 , 1 , 3 , 46 6,37,2,38,1,3,46
IgorLugansk [536]
Answer:
Mean: 19
Median: 6
Step-by-step explanation:
Answer:25x=320=12.8
Step-by-step explanation:
a number=x
x*25=25x
25x=320
320/25=12.8
x=12.8