Answer:
Port security and violation mode.
Explanation:
A switch is a layer two device of the OSI model. It is used to transmit frames between nodes within a network. It transfers frames by discovering the destination Mac address and saving it to its address table, and sending the frame to the egest port to the destination.
The port security command is used to specify the Mac addresses that are recognised by a port. There are three types of port security, they are, dynamic, static and sticky Mac addresses that can configured on an interface.
The security violation command is used to decide what happens to a port when it detects an unfamiliar Mac address. The three security violation modes are protect, restrict and shutdown. It is used as an interface command alongside the port security command.
Answer:
Salting
Explanation:
Salting is an idea that is related to hashing of password which is the mapping of input data to a fixed length output data by the use of algorithms.
Salting is the addition of a distinctive value to the beginning or end of a password in order to form a different hash value from the hash value that would have been generated without the 'salt', thereby making the passwords more secure from attacks
The salt for each user is a unique value that is stored along with the username in a database
The diagram of the of a ten-node network that uses ten routers is given in the image attached.
<h3>What is a node in a network?</h3>
A network node is known to be be seen as the kind of connection point that is seen amidst some network devices such as routers, printers, etc.
Note that they are known to often receive and send data from one network or endpoint to another.
Therefore, The diagram of the of a ten-node network that uses ten routers is given in the image attached.
Learn more about routers from
brainly.com/question/24812743
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Answer:
Given that:
A= 40n^2
B = 2n^3
By given scenario:
40n^2=2n^3
dividing both sides by 2
20n^2=n^3
dividing both sides by n^2 we get
20 = n
Now putting n=20 in algorithms A and B:
A=40n^2
= 40 (20)^2
= 40 * (400)
A= 16000
B= 2n^3
= 2 (20)^3
= 2(8000)
B= 16000
Now as A and B got same on n = 20, then as given:
n0 <20 for n =20
Let us take n0 = 19, it will prove A is better than B.
We can also match the respective graphs of algorithms of A and B to see which one leads and which one lags, before they cross at n= 20.
Answer:
In order to calculate area of a square, 'A' be the area of square and the length of the square be 'a'. Then we need to calculate A= a*a. Step 2 :- Accept as input, the length of the sides of the square, and store the value in variable a. Step 3 :- Calculate the area of the square (a*a) and store in a variable A.
Explanation:
