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murzikaleks [220]
3 years ago
10

In what form do the hexadecimal numbers need to be converted for a computer’s digital circuit to process them?

Computers and Technology
1 answer:
MrMuchimi3 years ago
5 0

Hexadecimal numbers are just a convenient representation of binary data. When entered as text, they consist of ASCII characters 0-9 and a-f. The numbers will then have to be converted to binary. This is accomplished by converting to uppercase, subtracting the ASCII offset (48 for 0-9 or 55 for A-F), so that the result is a number between 0 and 15 (inclusive). This can be stored in computer memory to represent 4 bits.

Hexadecimal numbers represent binary numbers in the following way:

hex | binary

0 = 0000

1 = 0001

2 = 0010

3 = 0011

4 = 0100

5 = 0101

6 = 0110

7 = 0111

8 = 1000

9 = 1001

a = 1010

b = 1011

c = 1100

d = 1101

e = 1110

f = 1111

As you can see, no other 4 bit combination exists.



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Read 2 more answers
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# include <iostream.h>

# include <stdio.h>

# include <string.h>

using namespace std;

class citizen

{      

    int i;

    public string name[30];

    public long int phonenumber[30];

    public void addindividual(string name1)

     {      

           If (i<=30)

            {     int flag=0;

                  for(int j=0; j<=i;j++)

                  {

                     if (strcmp(name[i], name1)

                      {

                          flag=1;

                      }

                     else

                     {  

                           flag=0;

                     }

                  }

                  If (flag)

                 {

                  if (i<30)

                  {

                  for(j=i+1;j<=30; j++)

                  {

                        cout<<"Enter the name:"; getchar(name[j]);

                        cout<<"Enter the phone number:"; cin>>phonenumber[j];

                         i++;

                   }

                  else  

                   {

                        cout<<"The person already exists";

                        exit();

                   }

              }

            else

             {

                 cout<<"array is full:";

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             }

     }

}

Void main()

{

     string str;

    cout<<" Enter name:";

    getline(cin, str); ;

     citizen c1=new citizen();

     c1.addindividual(name1);

}

Explanation:

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