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Reil [10]
3 years ago
15

Select all the expressions that are equivalent to 18 + 4(m − 3) + 4m.

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0

Answer:

  • 2(4m + 3)
  • 8m + 6

Hope it helps

mixas84 [53]3 years ago
4 0

Answer:

A 2(4m + 3)   Distribute 8m +6   match

C 8m + 6    This matches

Step-by-step explanation:

18 + 4(m − 3) + 4m

First distribute

18+ 4m -12 +4m

Then combine like terms

8m +6

Now see which expressions match

A 2(4m + 3)   Distribute 8m +6   match

D 4(2m + 4)  Distribute  8m + 16   no match

B 5m + 19  This does not have 8m   no match

E 8m + 16  This does not have 6 as a constant  no match

C 8m + 6    This matches

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Lelechka [254]

Answer:

The intersection of N and M contains only those elements that are in both N and M.

The intersection of N and M is ϕ.

​N∩M=∅

Step-by-step explanation:

Given

M = { 1, 2, 3, 5, 8, 13}

N = {-9, -8, -6, -4, -2, 4}

Now let us see each statement one by one.

The intersection of N and M contains only those elements that are in both N and M.

The statement is true because by definition intersection of two sets consists of common elements of both sets.

The intersection of N and M is ϕ.

The statement is true. As there is no common element in both sets.

The intersection of N and M is {−9,−8,−6,−4,−2}.

The statement is false because there is not common element in M and N.

N∪M=∅

The statement is false as the union consists of elements of both sets so it can't be empty.

​N∩M=∅

True. Because no common element so intersection will be an empty set..

4 0
3 years ago
5.
ANTONII [103]

The greatest possible number of club members is 7

<em><u>Solution:</u></em>

Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks

Each set can be divided equally among the club members

To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 49 and 21:</u></em>

The factors of 21 are: 1, 3, 7, 21

The factors of 49 are: 1, 7, 49

Then the greatest common factor is 7

Thus, the greatest possible number of club members is 7

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Answer:

Step-by-step explanation: she only has 3 because of herself

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Mademuasel [1]
12-9=3
3+9=12

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