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Reil [10]
2 years ago
15

Select all the expressions that are equivalent to 18 + 4(m − 3) + 4m.

Mathematics
2 answers:
shepuryov [24]2 years ago
7 0

Answer:

  • 2(4m + 3)
  • 8m + 6

Hope it helps

mixas84 [53]2 years ago
4 0

Answer:

A 2(4m + 3)   Distribute 8m +6   match

C 8m + 6    This matches

Step-by-step explanation:

18 + 4(m − 3) + 4m

First distribute

18+ 4m -12 +4m

Then combine like terms

8m +6

Now see which expressions match

A 2(4m + 3)   Distribute 8m +6   match

D 4(2m + 4)  Distribute  8m + 16   no match

B 5m + 19  This does not have 8m   no match

E 8m + 16  This does not have 6 as a constant  no match

C 8m + 6    This matches

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D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she
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Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:  

\frac{i}{e}=\frac{5}{3}

Let's multiply both sides by e. This yields:

i=\frac{5}{3}e

We know that when the income is <em>increased</em> by 5000 and the expenditures are <em>decreased </em>by 3000, the new ratio is 5:2. So, we can write the following proportion:

\frac{i+5000}{e-3000}=\frac{5}{2}

Let's multiply both sides by (e-3000):

i+5000=\frac{5}{2}(e-3000)

Since we know that i=\frac{5}{3}e, substitute:

\frac{5}{3}e+5000=\frac{5}{2}(e-3000)

So, let's solve for the expenditures. Distribute the right:

\frac{5}{3}e+5000=\frac{5}{2}e-7500

Subtract \frac{5}{2}e from both sides:

-\frac{5}{6}e+5000=-7500

Subtract 5000 from both sides:

-\frac{5}{6}e=-12500

Multiply both sides by -6/5. So, the expenditures are:

e=\text{Rs }15000

We can use the original ratio to find Sunayana's income:

i=\frac{5}{3}e

Substitute 15000 for e. Evaluate:

i=\frac{5}{3}(15000)=\text{Rs }25000

So, Sunayana's income is ₹25000 and expenditures are ₹15000.

And we're done!

Edit: Wrong currency, sorry about that!

3 0
3 years ago
Read 2 more answers
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Use the Pythagoras' Theorem:

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2 years ago
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