<span>ABCD is an isosceles trapezoid with legs AB and CD
∴ AB = CD
</span>
<span>AB = 6y +5
</span>
<span>CD= 2y +1
∴ 6y + 5 = 2y + 1
6y - 2y = 5 - 1
4y = 4
∴ y = 4/4 = 1
</span>
The answer is −10d4+17d2s−6s2
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Its a. 882÷6= 147. hope this helps
Answer:
1) 100 ) 15
Step-by-step explanation:
1) 30 to 50 is 20 miles so 5 * 20 is 100
2)20 to 50 is 30 miles so its 150 and 15 to 20 is 5 so 11 *5 is 55
55+150 equals 250 so the answer is 15 miles.