All categories

3 years ago

a cell phone costing R747 was advertised at a reduced price of R599.Calculate the percentage discount being offered

Mathematics

1 answer:

lana [24]3 years ago

6 0

Answer:

19.81% off

Step-by-step explanation:

percentage decrease = new-old/old

599-747/ 747 = -148/747

-148/747 x 100 = -19.81%

so the price has been reduced by 19.81%

You might be interested in

What is the solution to the linear equation? 4b + 6 = 2 – b + 4

Lady_Fox [76]

Answer:

The answer is b=0

Step-by-step explanation:

Add b to both sides

5b+6=2+4

combine like terms

5b + 6= 6

subtract 6 from both sides

5b=0

divide

b=0

hope this helped

5 0

2 years ago

Read 2 more answers

Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?

Viktor [21]

Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
$\frac{y-5}{x-7} = \frac{1}{10}$
y-5= $\frac{1}{10} {x-7}$
y-5= $\frac{1}{10} x- \frac{7}{10}$
y= $\frac{1}{10} x- \frac{43}{10}$

6 0

3 years ago

Read 2 more answers

Given f(x) = 2x² + 4 and g(x) = 3x – 1 …… What is (fg)(x)? Show your work.

Lelu [443]

Answer:

(fg)(x) = 6x³ - 2x² + 12x - 4

Step-by-step explanation:

( f g ) ( x ) = f ( x ) * g ( x )

f(x) = 2x² + 4

g(x) = 3x – 1

( f g ) ( x ) = (2x² + 4) (3x – 1)

= 6x³ - 2x² + 12x - 4

6 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Find two consecutive odd integers whose sum is -88

Flauer [41]

Hello there!

Make it an equation:

x + x + 2 = -88
2x + 2 = -88
2x = -88 + 2
2x = -86
x = -86/2
x = -43.

The numbers are -43 and -45.

Hope This Helps You!
Good Luck :)

6 0

3 years ago

Read 2 more answers

a cell phone costing R747 was advertised at a reduced price of R599.Calculate the percentage discount being offered ​

a cell phone costing R747 was advertised at a reduced price of R599.Calculate the percentage discount being offered