Answer:
XT=6 units
Step-by-step explanation:
The picture of the question is the attached figure
step 1
In the right triangle RST
Applying the Pythagorean theorem

we have
---> by segment addition postulate
substitute
----> equation A
step 2
In the right triangle RTX
Applying the Pythagorean theorem

we have

substitute


----> equation B
step 3
In the right triangle XTS
Applying the Pythagorean theorem

we have

substitute


----> equation C
step 4
equate equation B and equation C


----> equation D
step 5
Solve the system
----> equation A
----> equation D
Solve by elimination
Adds equation A and equation D

Find the value of RT^2

step 6
Find the value of XT
equation C

Answer:
4+ 8y
Step-by-step explanation:
(x - a)^2 + (y - b)^2 = r^2 is a circle with centre at (a, b) and radius of r
The correct answer is (x - 2)^2 + (y + 10)^2 = 9 ie the first one
Answer: x=-20
Step-by-step explanation:
Isolate the variable(x) by dividing each side by factors (50) that do not contain the variable.
so, is a semi-circle, half a circle, recall a circle has a total of 360°, so half of that will be 180°.
the diameter of that circle is 10, so its radius is half that, or 5.
![\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =180\\ r=5 \end{cases}\implies s=\cfrac{(180)(\pi )(5)}{180}\implies s=5\pi \stackrel{\pi =3.14}{\implies s=15.7}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%20s%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%7D%7B180%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3Dangle~in%5C%5C%20%5Cqquad%20degrees%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%5Ctheta%20%3D180%5C%5C%20r%3D5%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Ccfrac%7B%28180%29%28%5Cpi%20%29%285%29%7D%7B180%7D%5Cimplies%20s%3D5%5Cpi%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B%5Cimplies%20s%3D15.7%7D)