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irakobra [83]
3 years ago
13

7 yr 27 mon 27 da + 26 mo 42 da = i need answer aszap

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0

Answer:

11 years 7 months 7 days(if 31 days a months) and change 7 days to 9 days if assuming 30 days a moths

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If RX=4 and XS=9, then XT=<br> And how do you get it?
konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

RS^2=RT^2+TS^2

we have

RS=RX+XS=4+9=13\ units ---> by segment addition postulate

substitute

RT^2+TS^2=169  ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

RT^2=RX^2+XT^2

we have

RX=4\ units

substitute

RT^2=4^2+XT^2

RT^2=16+XT^2

XT^2=RT^2-16 ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

TS^2=XS^2+XT^2

we have

XS=9\ units

substitute

TS^2=9^2+XT^2

TS^2=81+XT^2

XT^2=TS^2-81 ----> equation C

step 4

equate equation B and equation C

TS^2-81=RT^2-16

TS^2-RT^2=81-16

TS^2-RT^2=65 ----> equation D

step 5

Solve the system

RT^2+TS^2=169 ----> equation A

TS^2-RT^2=65 ----> equation D

Solve by elimination

Adds equation A and equation D

RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117

Find the value of  RT^2

RT^2+117=169\\RT^2=52

step 6

Find the value of XT

equation C

XT^2=117-81\\XT^2=36\\XT=6\ units

7 0
3 years ago
Write an expression for the area of the triangle. Simplify the expression.
Rudik [331]

Answer:

4+ 8y

Step-by-step explanation:

7 0
3 years ago
Which is an equation of a circle with center (2, −10) and radius 3
stepladder [879]
(x - a)^2 + (y - b)^2 = r^2 is a circle with centre at (a, b) and radius of r
The correct answer is (x - 2)^2 + (y + 10)^2 = 9 ie the first one
6 0
3 years ago
50= -2.5x<br> can someone help me solve this? thank you!
Katarina [22]

Answer: x=-20

Step-by-step explanation:

Isolate the variable(x) by dividing each side by factors (50) that do not contain the variable.

6 0
3 years ago
Read 2 more answers
Find the arc length of the semicircle. 7the grade
charle [14.2K]

so, is a semi-circle, half a circle, recall a circle has a total of 360°, so half of that will be 180°.

the diameter of that circle is 10, so its radius is half that, or 5.


\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =180\\ r=5 \end{cases}\implies s=\cfrac{(180)(\pi )(5)}{180}\implies s=5\pi \stackrel{\pi =3.14}{\implies s=15.7}

3 0
3 years ago
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