Solution:
Given: zj = 3- j2, zz = - 4 + j3
Part a:
zj = 3- j2 = 
zz = - 4 + j3 = 
Part b:
|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60
|z1| = √(3− j2)(3+ j2) = √
13 = 3.60.
Part c:
With the help of part a:
z1z2 = 
Answer:
see below!!
Step-by-step explanation:
x + 3y = 5,
y = –x + 3
Substitute the point into each equation and verify that it is true
x + 3y = 5, 2 +3(1) = 5 5 = 5 true
y = -x +3 1 = -2+3 1=1 true
(2,1) is a solution
If you calculate 20^10/4^42 then you will find out it equals25
A. would be the answer because if you distribute/factor the expression you would get A.