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bulgar [2K]
3 years ago
6

When was "Rick Astley Never Gonna Give You Up" originally made?

Computers and Technology
2 answers:
Zepler [3.9K]3 years ago
6 0

Answer: See explanation

Explanation:

Rick Astley "Never Gonna Give You Up" was originally recorded in October 1986 and was then released on 27th July, 1987.

The song was recorded in South London at the PWL studios. On the American billboard hot 100, it reached number one in March 1988.

Pavlova-9 [17]3 years ago
5 0

Answer:

1987

Please mark me as brainliest

Explanation:

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Array, destination contains the number of 10 cities numbered 1 to 10 that the products were shipped to. Hence, 10 quantities of
Naddik [55]

Answer:

#include <stdlib.h>

#include <stdio.h>

void func1(int product[]){

int orders[6]={0};

for(int i=0;i<70;i++){

orders[product[i]]++;

}

printf("Total number of each type of products that were bought\n");

for(int i=1;i<=5;i++){

printf("Product %d = %d\n",i,orders[i]);

}

}

void func2(int product[],int quantity[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

total_cost+= price[product[i]]* quantity[i];

}

printf("The total cost of all 70 orders = %.2f\n",total_cost);

}

void func3(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]==8){

total_cost+= price[product[i]]* quantity[i];

}

}

printf("The total cost of all products shipped to destination 8 = %.2f\n",total_cost);

}

void func4(int product[],int quantity[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders where each order is $50 or more = %d\n",total_orders);

}

void func5(int product[],int quantity[],int origination[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %d\n",total_orders);

}

void func6(int product[],int quantity[],int origination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]] * quantity[i]>=50){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %.2f\n",total_cost);

}

void func7(int origination[],int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_orders++;

}

}

printf("The total number of orders that originated from 3 and shipped to 8. = %d\n",total_orders);

}

void func8(int product[],int quantity[],int origination[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total cost of orders that originated from 3 and shipped to 8. = %.2f\n",total_cost);

}

void func9(int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_orders++;

}

}

printf("The total number of orders that was shipped to all destinations except to 8. = %d\n",total_orders);

}

void func10(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_cost += price[product[i]] * quantity[i];;

}

}

printf("The total cost of orders that was shipped to all destinations except to 8. = %.2f\n",total_cost);

}

int main(){

int product[70] = {4, 2, 4, 2, 4, 5, 5, 2, 2, 5, 5, 4, 3, 5, 4, 2, 5, 3, 1, 2, 2, 3, 3, 4, 5, 5, 4, 5, 3, 5, 5, 1, 4, 5, 1, 5, 3, 2, 4, 1, 2, 4, 5, 1, 5, 5, 5, 5, 5, 2, 5, 1, 4, 4, 4, 2, 3, 3, 3, 3, 4, 3, 5, 5, 3, 2, 3, 5, 3, 2};

int quantity[70] = {10, 9, 6, 4, 10, 4, 9, 6, 10, 7, 3, 4, 4, 9, 1, 8, 9, 1, 5, 8, 7, 2, 3, 4, 10, 5, 6, 2, 1, 7, 2, 8, 6, 9, 8, 8, 7, 7, 9, 10, 6, 7, 8, 2, 1, 7, 6, 3, 3, 1, 8, 4, 10, 7, 1, 10, 6, 9, 8, 2, 4, 6, 1, 8, 2, 6, 10, 2, 6, 2};

int origination[70] = {2, 7, 5, 5, 7, 2, 7, 2, 7, 7, 5, 2, 5, 5, 5, 2, 2, 7, 2, 7, 7, 2, 2, 2, 2, 5, 7, 5, 7, 7, 5, 5, 2, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 2, 7, 2, 7, 5, 2, 2, 2, 5, 7, 2, 5, 5, 5, 7, 7, 2, 5, 2, 7, 5, 2, 5, 7};

int destination[70] = {8, 7, 3, 10, 2, 6, 4, 5, 1, 3, 5, 9, 5, 8, 6, 4, 3, 7, 1, 2, 7, 2, 8, 2, 2, 1, 2, 6, 10, 2, 7, 7, 8, 6, 8, 8, 4, 8, 3, 10, 6, 9, 4, 9, 5, 1, 7, 3, 1, 7, 5, 5, 4, 9, 3, 10, 8, 1, 1, 1, 1, 8, 10, 3, 5, 2, 8, 7, 4, 10};

float price[6]={0,11.95,7.95,19.95,24.95,15.25};

func1(product);

func2(product,quantity,price);

func3(product,quantity,destination,price);

func4(product,quantity,price);

func5(product,quantity,origination,price);

func6(product,quantity,origination,price);

func7(origination,destination);

func8(product,quantity,origination,destination,price);

func9(destination);

func10(product,quantity,destination,price);

}

Explanation:

The program inputs order, products and cities products are shipped.

After a series of conditional requirements being met, will output the destination each product os going to and the number of products with its associated price.

3 0
3 years ago
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The scheme where you can find the greatest common divisor of two integers by repetitive application of the division algorithm is
gavmur [86]

Answer:

False

Explanation:

The scheme where you can find the greatest common divisor (GCD) of two integers by repetitive application of the division algorithm is known as Euclidean Algorithm.

The Euclidean Algorithm for calculating GCD of two numbers X and Y can be given as follows:

  • If X=0 then GCD(X, Y)=Y since the Greatest Common Divisor of 0 and Y is Y.
  • If Y=0 then GCD(X, Y)=X since the Greates Common Divisor of 0 and X is X.
  • Let R be the remainder of dividing X by Y assuming X > Y. (R = X % Y)
  • Find GCD( Y, R ) because GCD( X, Y ) = GCD(Y, R ).
  • Repeat the above steps again till R = 0.

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ddd [48]
I think it is command and the key letter I at the same time
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