2. ***HINT: IQR = Q3 - Q1*
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Answer:
Step-by-step explanation:
First you need to put the equation in slope intercept form.
y = mx + b (m = slope and b = y-intercept)
5x + 2y = 12 (subtract 5x)
2y = -5x + 12 (now you need to isolate y. Therefore, divide all by 2)
y = -5/2x + 6
Now you have your slope and y-intercept. Your y-intercept will be 6. So on the graph you need to begin at 6 on the y-axis <em>(the line that goes up and down)</em>. Make your first point there. Your slope is the -5/2x. Slope is looked at as rise/run. This means from your point at 6, you will go down <em>(down because it's negative. If it was a positive, you would go up, i.e rise)</em> 5 units. Then you will go over to the right 2 units <em>(to the right because it is positive. Only the top one will be negative.)</em> Place your point once you have done that. Then draw a line between those two points.
<u>(note that on my screenshot, the tiny squares do </u><u>not</u><u> equal 1 unit. The larger ones with the bunch of tiny squares inside equal 1 unit)</u>
I hope this helped :)
