Solving equations simple
4n + 3 =11
So the 4 represents the amplitude of the function. We can also see that because it is a positive number, the graph is even. ⁽⁽The number before the graph type (Sin or Cos) always represents the amplitude. The amplitude is how many units the graph travels up and down from the midline.
The -2 is the midline. This means that the midline is at -2 on the Y-axis. To find the max and min, you then add the amplitude to find the maximum, and subtract to find the minimum. [-6. 2]
To find the period, you divide 2π by the term in front of x. In this case, it's 3, so we do 2π/3. This cannot be simplified further, but in degrees this equals 120°. This means that, with the question asking for 2 full cycles, that the graph will go through 2 full cycles in 240°
Hope this helps, sorry i couldn't sketch the graph for you
Answer:
The compounded annually account will earn more interest over 10 years
Step-by-step explanation:
The rule of the simple interest is I = Prt, where
The rule of the compounded interest is A = P
, where
- n is the number of periods
The interest I = A - P
∵ Each account start with $200
∴ P = 200
∵ They have an interest rate of 5%
∴ r = 5% = 5 ÷ 100 = 0.05
∵ One account earns simple interest and the other is compounded
annually
∴ n = 1 ⇒ compounded annually
∵ The time is 10 years
∴ t = 10
→ Substitute these values in the two rules above
∵ I = 200(0.05)(10)
∴ I = 100
∴ The simple interest = $100
∵ I = A - P
∵ A = 200
∴ A = 325.7789254
∵ I = 325.7789254 - 200
∴ I = 125.7789254
∴ The compounded interest = $125.7789254
∵ The simple interest is $100
∵ The compounded interest is $125.7789254
∵ $125.7789254 > $100
∴ The compounded annually account will earn more interest
over 10 years
The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
Learn more on mirror equation here; brainly.com/question/27924393
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