9514 1404 393
Answer:
64, 32, 16, 8
Step-by-step explanation:
The recursive definition tells you the first term is 64, and each succeeding term is 1/2 the one before. List 64, and keep dividing by 2 until you get the requested 4 terms.
64, 32, 16, 8
Answer:
- The relationship between the number of months after the first year and the amount on the remaining card is linear and inverse ( Which meant that ,when the number of months after the first year increases , the amount on the remaining car decreases , in a linear way ) .
- The Independent variable is the <u>numbers of months after the first year .</u>
- The Dependent variable is the<u> </u><u>amount on the remaining card , Bcoz this amount depends on the time it has passed since the first year , ( which is our independent variable!).</u>
- <u>If </u><u>we </u><u>call </u><u>"</u><u>Y"</u><u> </u><u>our </u><u>dependent</u><u> </u><u>variables</u><u> </u><u>and </u><u>"</u><u>X"</u><u> </u><u>our </u><u>Independent</u><u> </u><u>variable</u><u> </u><u>,</u><u> </u><u>This </u><u>relationship</u><u> </u><u>can </u><u>be </u><u>written</u><u> </u><u>as </u><u>Y=</u><u> </u><u>2</u><u>5</u><u> </u><u>-</u><u> </u><u>2</u><u>.</u><u>5</u><u>x</u><u>.</u>
- <u>If </u><u>no </u><u>months </u><u>had </u><u>passed </u><u>since </u><u>the </u><u>first</u><u> </u><u>year,</u><u> </u><u>then </u><u>x=</u><u> </u><u>0</u><u> </u><u>and </u><u>the </u><u>amount</u><u> </u><u>in </u><u>the </u><u>card </u><u>equals </u><u>$</u><u>2</u><u>5</u><u> </u><u>,</u><u> </u><u>While </u><u>if </u><u>one </u><u>month </u><u>has </u><u>passed </u><u>since </u><u>the </u><u>first </u><u>year </u><u>x=</u><u> </u><u>1</u><u> </u><u>and </u><u>y=</u><u> </u><u>2</u><u>2</u><u>.</u><u>5</u><u> </u><u>(</u><u> </u><u>The </u><u>amount</u><u> </u><u>in </u><u>the </u><u>card </u><u>in </u><u>this </u><u>case </u><u>is </u><u>$</u><u>2</u><u>2</u><u>.</u><u>5</u><u> </u><u>.</u>
Step-by-step explanation:
<h2>Hope this helps you !! </h2>
Use Moivre Formula to find cube roots of 64(cos219+isin219)
Cubic roots =∛[64(cos219+isin219)] = [64(cos219+isin219)]^(1/3)
= 4[(cos219+isin219)]^(1/3)=4[cos(219)/3+isin219/3)]=
= 1.169 + 3.82 i
Answer to the problem is 18x^4
Answer:
<h2>-3n = 27</h2>
Step-by-step explanation:
The product of a number and negative three is twenty-seven.
<em>n - </em><em>a number</em>
the product of a number and negative three: <em>n · (-3) = -3n</em>