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zhannawk [14.2K]
3 years ago
7

A cereal box has a height of 10 inches, a length of 8 inches, and a width of 2 inches. What is the surface area of the cereal bo

x?
Mathematics
2 answers:
Irina18 [472]3 years ago
5 0

Answer:

232 in^2

Step-by-step explanation:

Using the formula for surface area A=2(wl+hl+hw)

A=2(16+80+20)

A=232

murzikaleks [220]3 years ago
3 0

Answer:

A = 232

Step by step explanitation:

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Devon is trying to find the unit price on a 6-pack of drinks on sale for $2.99. His sister says that at that price, each drink w
Mars2501 [29]

Answer:

No

2.99/6 = about fifty cents a drink.

(sorry if its not right I havent done this kind of math in like 3-5 years lol)

8 0
3 years ago
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HELP ASAP PLEASE!!!!!!!!!!!!!!!
TiliK225 [7]
ITS D!! It’s the third option !!
8 0
3 years ago
3 ft<br> 10 ft<br> Perimeter:<br> Area:
Crazy boy [7]

Step-by-step explanation:

The area = 3 × 10 = 30

The perimeter = 2(3 + 10) = 26

please give me a brainliest answer

8 0
2 years ago
Solve for t.<br><br> t/-3.2 &lt; 5
Black_prince [1.1K]

Step-by-step explanation:

t/-3,2 < 5

t > 5 × -3,2

t >-16

4 0
3 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
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