when using a clamp and ring stand to hold glassware and tools, what is the best position for the clamp?

An ostrich runs north in a straight line for 21 meters. She then turns around and runs 25 meters back toward her nest (south) on

drek231 [11]

The ostrich runs 21 N then goes back by 25 S

The displacement is -4 S

21 - 25 = -4

6 0

3 years ago

When the equation Ca(OH)2 + HBr → (products) is completed and balanced, one term in the equation will be

NISA [10]

Answer for the given question is CaBr2. Although, the given equation requires balancing of by adding one more HBr and one more H2o in resultant. The given equation will product at least one CaBr2. Hence the answer for the given equation is Calcium bromide i.e. CaBr2.

4 0

2 years ago

given the diagram below which contains a mixture of three acids in an aqueous solution, identify the color of the sphere that re

charle [14.2K]

The acid having the yellow anion is a weak acid.

The weak acid is the acid that does not dissociate completely in solution. Strong acids are known to dissociate completely in solution. Hence, their cations and anions do not occur together in solution.

Weak acids acids do not dissociate in solution hence, we can still spot the cations connected to their anions in solution. Hence, the acid having the yellow anion is a weak acid.

Learn more: brainly.com/question/8743052

7 0

2 years ago

The Surface of Earth is changing slowly over time.A.False B.true Previous

oksian1 [2.3K]

Answer:

true

Explanation:

7 0

3 years ago

A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm

Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 $^{\circ}C$ = 328 K

Initial pressure = P = 845 mmHg

Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$

The final temperature is 407.57 K

7 0

2 years ago