Answer:
- neither even nor odd
- degree 5
- LC negative
- roots {-6, -4, 0, 2, 3}
Step-by-step explanation:
The function's graph is not symmetrical about the origin, so it is not an odd function. It is not symmetrical about the y-axis, so is not an even function.
The function is neither even nor odd.
There are 5 zero-crossings and no places where y=0 and the graph does not cross. This means the function is of degree 5, at least.
The general shape of the function is down and to the right, so the sign of the function for large values of x is opposite the sign of x. The leading coefficient must be negative.
As we noted, there are 5 zero-crossings. These are the real roots. They are found at x-values in the set {-6, -4, 0, 2, 3}.
The answer is B. It's B because a straight line has a degree of 180, if you have 2, then of course it becomes 360. In B, you have 90, 90, and 150. If one of the angles is 30, you add that onto 150 to get 180 and add 90 and 90 together to get 180. Naturally, add those two answers together to get 360.
C) 88
Explanation: trust me
Problem 9.
Using the Angle Addition Postulate,
m<QRS + m<SRT = m<QRT
Now we replace the measures of the three angles above with the value or expressions we are given, and we solve for x.
2x + 8 + 3x + 14 = 82
5x + 22 = 82
5x = 60
x = 12
m<QRS = 2x + 8 = 2(12) + 8 = 24 + 8 = 32
Answer: 32 degrees
Problem 10.
Using the Angle Addition Postulate,
m<ABC + m<CBD = m<ABD
Now we replace the measures of the two angles above with the values we are given, and solve for the unknown angle.
115 + m<CBD = 180
m<CBD = 180 - 115
m<CBD = 65
Answer: m<CBD = 65 degrees
3.50+6x1.50=12.50+3.25=15.75-30=14.25
The answer is 14.25