Answer:
number 1. 5/4 number 2. 7/4 number 3. 1/5
Step-by-step explanation It's the shaped parts. Hope this helps : )
1. The problem indicates that 300 pounds of oranges were purchased at $0.24 per pound, so the cost is:
300x$0.24=$72
2. A percent of 21% spoilage is expected, which means that 89% of 300 pounds of oranges left, is:
300x0.89=267 pounds of oranges
3. We want to calculate the selling price per pound of 267 pounds of oranges, so let's call this value "x":
Markup %=(Markup/cost)x100
Markup=267x-72
4. The desired markup, based on selling price, is 50%. So, when we substitute the values, we obtain:
(267x-72/72)x100=50
5. Let's clear the "x":
(26700x-7200/72)=50
26700x-7200=50x72
26700x-7200=3600
26700x=3600+7200
x=10800/26700
x=$0.40
x=40 cents
What should the selling price per pound be?
The answer is: 40 cents or $0.40
Answer:
p = -9 ; open circle pointing left
Step-by-step explanation:
-7p + 3 < - 60
*subtract 3 from both sides*
-7p < -63
*divide both sides by -7*
p < -9
Answer with explanation:
The Data Set is→ 10,12,2,4,24,2,7,7,9
Arranging the data in ascending order
2,2,4, 7,7,9,10, 12, 24
Number of observation is odd,
So, Median
5th Observation = 7
=First Quartile of data set that is from first variate to Median value
={2,2,4,7,7}
So, 
=Third Quartile of data set that is from last variate to Median value
={7,9,10,12,24}
So, 
Minimum value in data set = 2
Maximum value in data set = 24
Plotting the Box plot
Option C , is correct Box plot.
Answer:
For questions 1 the answer is 5.567 x 10^6 and for 2 the answer is 3.67 x 10^9
Step-by-step explanation:
