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3 years ago

Please help i will give brainliest to the right answer.

Mathematics

1 answer:

zloy xaker [14]3 years ago

5 0

Answer:

Only these two -3+-4 and -3+(-4) are equal to -3-4

Step-by-step explanation:

Hope this helps!

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At George Washington High School the ratio of graduating seniors that go on to college, as compared to those who do not, is 7 :

wariber [46]

The solution to the problem is as follows:

<span>7(4)/4(4) = 28/16

28+16= 44
</span>
Therefore, the size of the graduating class would be 44 students in all.

I hope my answer has come to your help. God bless and have a nice day ahead!

7 0

3 years ago

Please help!!! Imagine is attached

Paul [167]

Answer:

They're both parabolas.

One is a parabola opening up (blue), the other one is opening down.

Step-by-step explanation:

In dutch, we call them what can be translated as mountain-parabolas and valley-parabolas.

I also saw the terms "concave up" and "concave down".

8 0

3 years ago

Identify the effect on the graph of replacing f(x) by A f(x)

JulijaS [17]

Answer:

See explanation

Step-by-step explanation:

Required

Effect of replacing $f(x)$ with $f(x - h)$

f(x) is represented as: (x,y)

While

f(x - h) is represented as (x - h, y)

Notice the difference in both is that, the x value in f(x - h) is reduced by a constant h while the y value remain unchanged.

This means that the graph of f(x) will shift horizontally (i.e. along the x-axis) to the left by h units

6 0

2 years ago

Find the distance between each pair of points.<br> (3,5) (2,-5)

Sholpan [36]

The distance between these points is (4,7) and (3,-7)

3 0

3 years ago

What function is increasing? will give brainlist !

Wewaii [24]

Answer:

Option B.

Step-by-step explanation:

Option A.

f(x) = $(0.5)^{x}$

Derivative of the given function,

f'(x) = $\frac{d}{dx}(0.5)^x$

= $(0.5)^x[\text{ln}(0.5)]$

= $-(0.693)(0.5)^{x}$

Since derivative of the function is negative, the given function is decreasing.

Option B. f(x) = $5^x$

f'(x) = $\frac{d}{dx}(5)^x$

= $(5)^x[\text{ln}(5)]$

= $1.609(5)^x$

Since derivative is positive, given function is increasing.

Option C. f(x) = $(\frac{1}{5})^x$

f'(x) = $\frac{d}{dx}(\frac{1}{5})^x$

= $\frac{d}{dx}(5)^{(-x)}$

= $-5^{-x}.\text{ln}(5)$

Since derivative is negative, given function is decreasing.

Option D. f(x) = $(\frac{1}{15})^x$

f'(x) = $-15^{-x}[\text{ln}(15)]$

= $-2.708(15)^{-x}$

Since derivative is negative, given function is decreasing.

Option (B) is the answer.

7 0

2 years ago