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3 years ago

15

At George Washington High School the ratio of graduating seniors that go on to college, as compared to those who do not, is 7 :

4. Last year 28 students went on to college. How large was the graduating class?

1 answer:

wariber [46]3 years ago

7 0

The solution to the problem is as follows:

<span>7(4)/4(4) = 28/16

28+16= 44
</span>
Therefore, the size of the graduating class would be 44 students in all.

I hope my answer has come to your help. God bless and have a nice day ahead!

You might be interested in

Find three consecutive even integers that sum up to -48

Igoryamba

We can write the equation: x + x + 2 + x + 4 = -48, where x is the least digit and x + 4 is the greatest. We get 3x + 6 = -48, 3x = -54. x = -18, so x + 2 is -20, and x + 4 is -22. Therefore, the 3 consecutive even integers that sum to -48 are -18, -20, and -22.
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Hope this helps!

4 0

3 years ago

Find the next three terms of the arithmetic sequence 5, 9, 13, 17, … .

Marizza181 [45]

Hi there!

The answer is D. 21, 25, 29

The arithmetic sequence has a pattern of +4. From 17 you add 4, resulting to 21 and you continue.

Hope this helps !

6 0

3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

A plastic bin in the shape of a cube contains 900 marbles, each with a volume of 8 in?. If the cube has side lengths of 2 feet,

qaws [65]

900 x 8 in , 2ft in cubic inches, guessing

8 0

2 years ago

What are the solutions for x when y is equal to 0 in the following quadratic

Scrat [10]

Answer: Option C

Step-by-step explanation:

Given the quadratic equation $y = x^2 - 13x$ , substitute $y=0$ :

$0 = x^2 - 13x$

In this case, to find the solutions of the given quadratic equation, you must factor out the variable "x". Then:

$0=x(x-13)$

Therefore, you get that the solutions of this equation are the following:

$x=0\\\\\\x-13=0\\x=13$

Then, the answer is:

$x = 0\ or\ x = 13$

This matches with the option C.

5 0

3 years ago