first off, is noteworthy that's the graph of an exponential function, thus the function will be along the lines of g(x) = abˣ , now, what's "a" and "b" values?
well, let's take a peek when x = 0 and x = 1.
![\bf g(x) = ab^x \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 0\\ y = 1 \end{cases}\implies 1=ab^0\implies 1=a(1)\implies \boxed{1=a} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} x = 1\\ y = 4 \end{cases}\implies 4 = ab^1\implies 4=1b^1\implies \boxed{4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill g(x) = 4^x\qquad \qquad \qquad \begin{array}{|c|c|ll} \cline{1-2} x&y\\ \cline{1-2} -2&\frac{1}{4^2}\to \frac{1}{16}\\ -1&\frac{1}{4}\\ 0&1\\ 1&4\\ 2&16\\ \cline{1-2} \end{array}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20g%28x%29%20%3D%20ab%5Ex%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20x%20%3D%200%5C%5C%20y%20%3D%201%20%5Cend%7Bcases%7D%5Cimplies%201%3Dab%5E0%5Cimplies%201%3Da%281%29%5Cimplies%20%5Cboxed%7B1%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20x%20%3D%201%5C%5C%20y%20%3D%204%20%5Cend%7Bcases%7D%5Cimplies%204%20%3D%20ab%5E1%5Cimplies%204%3D1b%5E1%5Cimplies%20%5Cboxed%7B4%3Db%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20g%28x%29%20%3D%204%5Ex%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cll%7D%20%5Ccline%7B1-2%7D%20x%26y%5C%5C%20%5Ccline%7B1-2%7D%20-2%26%5Cfrac%7B1%7D%7B4%5E2%7D%5Cto%20%5Cfrac%7B1%7D%7B16%7D%5C%5C%20-1%26%5Cfrac%7B1%7D%7B4%7D%5C%5C%200%261%5C%5C%201%264%5C%5C%202%2616%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D~%5Chfill)
The parabola divises the plan into 2 parts. Part 1 composes the point A, part 2 composes the points C, D, F.
+ All the points (x;y) satisfies: -y^2+x=-4 is on the <span>parabola.
</span>+ All the points (x;y) satisfies: -y^2+x< -4 is in part 1.
+ All the points (x;y) satisfies: -y^2+x> -4 is in part 2<span>.
And for the question: "</span><span>Which of the points satisfy the inequality, -y^2+x<-4"
</span>we have the answer: A and E
Answer:
yes it is correct
Step-by-step explanation:
subtract |p| from |p+q| to get |q|
Answer:
#16 = (0, -10)
#17 = (-18, -3)
Step-by-step explanation:
U wouldn't use the distance formula, you would need to use the Midpoint Formula, which is, M = (x1 + x2 / 2, y1 + y2 / 2). For #16, you plug in (4, -5) for M and 8 for x1 and 0 for y1, so the equation should look like this : (4, -5) = (8 + x2 / 2, 0 + y2 / 2). Then separate the equation to make it easier: 4 = 8 + x2 / 2 and the second equation : -5 = 0 + y2 / 2. So let's do the 1st equation, the first step would be to multiply the 2 to both sides. So the equation should look like this, 8 = 8 + x. Then subtract the 8 from both sides and you get 0 as your x. Now moving on to the 2nd equation, you multiply the 2 to both sides, and you get, -10 = 0 + y, as your equation, but since 0 won't affect it, -10 should be your y. Then just use these steps to solve #17, and your answer should be (-18, -3).
You should get photo math you can take a picture and it will give you the answer and show you how to solve it
