When carbon is burned in air carbon iv oxide gas is formed.
C (s) + O2 (g) = CO2(g) ΔH = - 393.5 kj/mol
The enthalpy change of the reaction is -393.5 j/mol which means that when one mole of carbon is completely burnt in air then 393.5 j of energy is evolved.
Thus, 1 mole = -393.5 j , then for 480 kj
= 480 × 1/393.5
= 1.2198 moles
1 mole of carbon iv oxide is equal to 44 g
thus, 1.2198 moles will be 1.2198 × 44 = 53.6712 g of CO2
Answer:
The temperatures on Earth increase
Explanation:
more energy results in more heat.
Chemical. Burning is a chemical process
Answer:
The exact result is 82.5 min (close to c. 80 min)
Explanation:
Hello,
In the following picture you'll find the numerical procedure for this exercise.
- Take into account that the initial concentration and the velocity constant remain constant for the two mentioned scenarios.
Best regards.
Ma = 1.66 M
Va = 30.7 mL
Mb = 0.704 M
Vb = 16.7 mL
Using the law <span>of dilution :
</span>
Mf = Ma x Va + Mb x Vb / Va + Vb
Mf = 1.66 x 30.7 + 0.704 x 16.7 / 30.7 + 16.7
Mf = 50.962 + 11.7568 / 47.4
Mf = 62.7188 / 47.4
Mf = 1.323 M
hope this helps!
